摘要:
#include<bits/stdc++.h>using namespace std;typedef long long LL;const int N = 1e6 + 7;int a[N];LL ans,all; void dfs(int x, LL y){ if(x>a[0]){ans+=all/ 阅读全文
摘要:
#include<bits/stdc++.h>using namespace std;const int N=2;const int MOD=10000;struct MAT{int a[N][N];}; MAT operator*(MAT x, MAT y){ MAT z; for(int i=0 阅读全文