380. Insert Delete GetRandom O(1)
Design a data structure that supports all following operations in average O(1) time.
insert(val)
: Inserts an item val to the set if not already present.remove(val)
: Removes an item val from the set if present.getRandom
: Returns a random element from current set of elements. Each element must have the same probability of being returned.
Example:
// Init an empty set. RandomizedSet randomSet = new RandomizedSet(); // Inserts 1 to the set. Returns true as 1 was inserted successfully. randomSet.insert(1); // Returns false as 2 does not exist in the set. randomSet.remove(2); // Inserts 2 to the set, returns true. Set now contains [1,2]. randomSet.insert(2); // getRandom should return either 1 or 2 randomly. randomSet.getRandom(); // Removes 1 from the set, returns true. Set now contains [2]. randomSet.remove(1); // 2 was already in the set, so return false. randomSet.insert(2); // Since 2 is the only number in the set, getRandom always return 2. randomSet.getRandom();
此题解决了我很久以前的疑问,原来map的containsKey操作的时间复杂度是常数时间完成的,代码实现起来不是很难,做Arraylist的目的是获取random的时候用,hashmap的value值用来
设置list的索引值,代码如下:
1 public class RandomizedSet { 2 ArrayList<Integer> nums; 3 Map<Integer,Integer> map; 4 java.util.Random rand = new java.util.Random(); 5 /** Initialize your data structure here. */ 6 public RandomizedSet() { 7 nums = new ArrayList<Integer>(); 8 map = new HashMap<Integer,Integer>(); 9 } 10 11 /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */ 12 public boolean insert(int val) { 13 if(map.containsKey(val)){ 14 return false; 15 }else{ 16 map.put(val,nums.size()); 17 nums.add(val); 18 } 19 return true; 20 } 21 22 /** Removes a value from the set. Returns true if the set contained the specified element. */ 23 public boolean remove(int val) { 24 if(!map.containsKey(val)){ 25 return false; 26 }else{ 27 if(map.get(val)<nums.size()-1){ 28 int loc = map.get(val); 29 int value = nums.get(nums.size()-1); 30 nums.set(loc,value); 31 map.put(value,loc); 32 } 33 map.remove(val); 34 nums.remove(nums.size()-1); 35 return true; 36 } 37 } 38 39 /** Get a random element from the set. */ 40 public int getRandom() { 41 return nums.get(rand.nextInt(nums.size())); 42 } 43 } 44 45 /** 46 * Your RandomizedSet object will be instantiated and called as such: 47 * RandomizedSet obj = new RandomizedSet(); 48 * boolean param_1 = obj.insert(val); 49 * boolean param_2 = obj.remove(val); 50 * int param_3 = obj.getRandom(); 51 */