javascript reduce用法

(1)计算数组中每个元素出现的次数

 1 let names = ['Alice', 'Bob', 'Tiff', 'Bruce', 'Alice'];
 2 
 3 let nameNum = names.reduce((pre,cur)=>{
 4   if(cur in pre){
 5     pre[cur]++
 6   }else{
 7     pre[cur] = 1 
 8   }
 9   return pre
10 },{})
11 console.log(nameNum); //{Alice: 2, Bob: 1, Tiff: 1, Bruce: 1}

(2)数组去重

let arr = [1,2,3,4,4,1]
let newArr = arr.reduce((pre,cur)=>{
    if(!pre.includes(cur)){
      return pre.concat(cur)
    }else{
      return pre
    }
},[])
console.log(newArr);// [1, 2, 3, 4]

(3)将二维数组转化为一维

let arr = [[0, 1], [2, 3], [4, 5]]
let newArr = arr.reduce((pre,cur)=>{
    return pre.concat(cur)
},[])
console.log(newArr); // [0, 1, 2, 3, 4, 5]

(3)将多维数组转化为一维

let arr = [[0, 1], [2, 3], [4,[5,6,7]]]
const newArr = function(arr){
   return arr.reduce((pre,cur)=>pre.concat(Array.isArray(cur)?newArr(cur):cur),[])
}
console.log(newArr(arr)); //[0, 1, 2, 3, 4, 5, 6, 7]

 

posted on 2019-03-02 20:34  时光游弋  阅读(328)  评论(0编辑  收藏  举报