LeetCode 237. Delete Node in a Linked List 

 1 class Solution {
 2 public:
 3     void deleteNode(ListNode* node) {
 4         if(node == NULL || node->next == NULL){
 5             node = NULL;
 6             return;
 7         }
 8         ListNode* tmp = node->next;
 9         node->val = node->next->val;
10         node->next = node->next->next;
11         delete tmp;
12     }
13 };

node：要删除的节点

node->#1->#2

把#1的val赋给node，把node->next改为#2，删除#1.

posted @ 2016-03-10 20:13  co0oder  阅读(125)  评论(0)  编辑  收藏  举报