Python读取二进制文件

import os
import sys
import socket


mypath = sys.argv[1]

if not os.path.exists(mypath):
    print "The path %s does not exist!" % mypath
    sys.exit(2)

for f in [s for s in os.listdir(mypath) if os.path.splitext(s)[1] == ".csta"]:
    outputName  = f + ".csv"
    fd          = open(os.path.join(mypath, f), 'rb')
    outputFd    = open(os.path.join(mypath, outputName), 'w')
    fd.seek(0, 0)
    while True:
        s = int(0)
        for i in range(37632):
            data = fd.read(2)
            if len(data) == 0:
                break
            else:
                s += socket.htons(int(data.encode('hex'), 16))

        if len(data) == 0:
            break
        else:
            outputFd.write("%d\n" %s)
    fd.close()
    outputFd.close()    
    print "%s >> %s" % (f, outputName)

程序思路:

  1. 使用os.listdir列出用户所给目录的所有文件;
  2. 使用os.path.splitext获得文件的后缀名,以便匹配到自己想要的文件的类型;
  3. 使用data.encode('hex')获得十六进制的字符,然后使用int(data, 16)将其转成十进制数字;
posted @ 2016-09-28 15:47  朝雾之归乡  阅读(8845)  评论(0编辑  收藏  举报