摘要: 测试表:studentselect * from studnet;select count(distinct name) from student;select count(distinct *) from student;这样是有错误的,可以变通的实现select count(*) from(se... 阅读全文
posted @ 2014-12-11 16:43 cnmarkao 阅读(654) 评论(0) 推荐(0) 编辑