HDU 4371 Alice and Bob

比赛是木做出来,回头看看,是当时考虑的太复杂了,si = si-1 + dk or si = si-1 - dk , and si-2 < si<= n, 1 <= k <= m, i >= 3相减的不会去取,每次都加上个d

View Code
 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 
 4 int main()
 5 {
 6     int i, k, d, ncases;
 7     int n, m, dmin;
 8     
 9     scanf("%d", &ncases); 
10     for(k = 1; k <= ncases; k++)
11     {
12         scanf("%d%d",&n,&m);   
13        for(i=0; i<m; i++)
14        {     
15            scanf("%d",&d);  
16             if(i) 
17              dmin = d < dmin ? d : dmin;
18             else 
19               dmin = d; 
20        }  
21        n = n/dmin; 
22        printf("Case #%d: ",k); 
23       if((n+1)%2 == 0)
24          printf("Bob\n"); 
25       else   
26          printf("Alice\n");    
27     } 
28     system("pause");
29     return 0;
30 }   

 

min,

只要拿n/dmin+1判断结果是奇数还是偶数就可以了。当是奇数时,最后一个取数的一定是Bob,因为是Alice先去的,所以此时Bob赢。反之一定是Alice赢

 

 

posted @ 2012-08-18 11:01  zhongya  阅读(142)  评论(0编辑  收藏  举报