浙江省赛水题 A题

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 1 #include<stdio.h>
 2 #include<math.h>
 3 #include<stdlib.h>
 4 
 5 int main()
 6 {
 7     int ncases, d, t;
 8     double n1, n2, num1,num2,k;
 9     int sum1, sum2;
10     
11     scanf("%d",&ncases);
12     while( ncases-- )
13     {
14        scanf("%d%d",&d,&t);
15        num1 = 0.0; num2 = 0.0;     
16        if(d>=0 && d<=3)
17        {
18           num1 += 11;             
19           num2 += 11;
20        }
21        else if(d>3 && d<=10)
22        {
23           num1 = 11 + (d-3)*2.0;
24           num2 = 11 + (d-3)*2.5;
25        }
26        else if(d > 10)
27        {
28           num1 = 11 + 7*2.0 + (d-10)*3.0;   
29           num2 = 11 + 7*2.5 + (d-10)*3.75;  
30        }    
31        n1 = (t/5.0)*2;  
32        n2 = (t/4.0)*2.5;    
33        if((num1+n1)-floor(num1+n1) < 0.500000) 
34          sum1 = (int)(num1+n1); 
35        else
36          sum1 = (int)(num1+n1)+1;
37        if((num2+n2)-floor(num2+n2) < 0.5000000)
38          sum2 = (int)(num2+n2);  
39        else  
40          sum2 = (int)(num2+n2)+1; 
41        printf("%d\n",sum2-sum1);     
42     }  
43     return 0;
44 }   
45  
46
posted @ 2012-04-17 22:29  zhongya  阅读(134)  评论(0)  编辑  收藏  举报