python学习_1

numpy.array[  ]

#!/usr/bin/python3
# -*- coding: utf-8 -*-
# @Time    : 18-10-17 上午10:51
# @Author  : Guo Zhengbing
# @Email   : cn_gzb@126.com

import numpy

# print(help(numpy.genfromtxt))
a = numpy.array([5, 10, 25, 30])
b = numpy.array([[5, 1, 2], [23, 4, 9]])
# print(a)
# print(b) # 输出矩阵

# print(a.shape) # 输出这个矩阵的类型 N行M列
# print(b.shape)

# numbers = numpy.array([1, 2, 3, 4, '5'])
# print(numbers)
# print(numbers.dtype) # 输出类型
# 保证同一类型

# print(a[0:3]) # 矩阵切片

# print(b[:, 0]) # 取一个矩阵第1列
# print(b[:, 0: 2]) # 取一个矩阵前两列

matrix = numpy.array([
               [5, 10, 15],
               [3, 6, 9],
               [8, 7, 13]
            ])
# print(matrix[1:3, 0:2]) # 取几行几列

a = numpy.array([5, 10, 25, 30])
# a == 10
# print(a == 10) # 判断数组中各个元素是否是10
# print(matrix == 10) # 判断数组中各个元素是否是10

# equal = (a == 10)
# print(equal)
# print(a[equal]) #返回真实值

 

import numpy
# numpy中&(与) | 的用法
a = numpy.array([5, 10, 10, 20])
# equal = (a == 5) & (a == 10)
# print(equal)
# equal = (a == 5) | (a == 10)
# print(equal)

b = numpy.array(["1", "101", "20"])
c = numpy.array([2, 8, 10])
# print(b.dtype)
# print(b)
# b = b.astype(float)  # 将b中元素变成float型
# print(b.dtype)
# print(b)
# print(c.dtype)
print(c.min())

 

d = numpy.array([[58, 11, 2],
                 [23, 43, 9],
                 [20, 25, 3]
                 ])
print(d.sum(axis=1))  # 对每个行求和
print(d.sum(axis=0))   # 对每一个列求和

 

import numpy as np
print(np.arange(15))
a = np.arange(15).reshape(3, 5)   # 把行向量变成3行5列的举证
print(a)
print(a.shape)   # 打印行和列分别为多少
print(a.ndim)     # 打印维度
print(a.dtype.name)   # 打印类型
print(a.size)   # 打印数组中元素个数

output:
[ 0  1  2  3  4  5  6  7  8  9 10 11 12 13 14]
[[ 0  1  2  3  4]
 [ 5  6  7  8  9]
 [10 11 12 13 14]]
(3, 5)
2
int64
15

import numpy
array = numpy.zeros((3, 4))  # 构造一个m*n维的0矩阵
print(array)

[[0. 0. 0. 0.]
 [0. 0. 0. 0.]
 [0. 0. 0. 0.]]
import numpy as np
print(np.ones((2, 3, 4), dtype=np.int32))


[[1 1 1 1]
  [1 1 1 1]
  [1 1 1 1]]]
import numpy as np
# print(np.ones((2, 3, 4), dtype=np.int32))
print(np.arange(10, 32, 5))  # 输出一个这样的数组:从第一个数开始累加5,但是结果小于32


[10 15 20 25 30]
import numpy as np
print(np.arange(12).reshape(4, 3))   # 构造一个矩阵:0-11,四行三列


[[ 0  1  2]
 [ 3  4  5]
 [ 6  7  8]
 [ 9 10 11]]
生成随机种子:
import numpy as np
print(np.random.rand(2, 3))  # 两行三列的随机种子  从 0 -- +1 上的值(在python3.6中)


[[0.36246585 0.01616546 0.06700026]
 [0.14067238 0.24054495 0.60194616]]
import numpy as np
from numpy import pi
a = np.linspace(0, 2*pi, 100)  # 起始值为0,终点为2*pi,平均取100个值
print(a)



[0.         0.06346652 0.12693304 0.19039955 0.25386607 0.31733259
 0.38079911 0.44426563 0.50773215 0.57119866 0.63466518 0.6981317
 0.76159822 0.82506474 0.88853126 0.95199777 1.01546429 1.07893081
 1.14239733 1.20586385 1.26933037 1.33279688 1.3962634  1.45972992
 1.52319644 1.58666296 1.65012947 1.71359599 1.77706251 1.84052903
 1.90399555 1.96746207 2.03092858 2.0943951  2.15786162 2.22132814
 2.28479466 2.34826118 2.41172769 2.47519421 2.53866073 2.60212725
 2.66559377 2.72906028 2.7925268  2.85599332 2.91945984 2.98292636
 3.04639288 3.10985939 3.17332591 3.23679243 3.30025895 3.36372547
 3.42719199 3.4906585  3.55412502 3.61759154 3.68105806 3.74452458
 3.8079911  3.87145761 3.93492413 3.99839065 4.06185717 4.12532369
 4.1887902  4.25225672 4.31572324 4.37918976 4.44265628 4.5061228
 4.56958931 4.63305583 4.69652235 4.75998887 4.82345539 4.88692191
 4.95038842 5.01385494 5.07732146 5.14078798 5.2042545  5.26772102
 5.33118753 5.39465405 5.45812057 5.52158709 5.58505361 5.64852012
 5.71198664 5.77545316 5.83891968 5.9023862  5.96585272 6.02931923
 6.09278575 6.15625227 6.21971879 6.28318531]
import numpy as np
a = np.array([20, 30, 40, 50])
print(a<35)   # 判断大小


[ True  True False False]
import numpy as np
A = np.array([[1, 2],
              [0, 3]
              ])
B = np.array([[2, 0],
              [1, 3]
              ])
print(A*B)   # 相对位置相乘
print(A.dot(B))  # 矩阵乘法
print(np.dot(A, B))


[[2 0]
 [0 9]]
[[4 6]
 [3 9]]
[[4 6]
 [3 9]]

 

import numpy as np
a = np.transpose([[1, 2, 3], [1, 2, 3], [1, 2, 3]])
print(a)
b = np.transpose(a).tolist()
c = a.T
print(b)
print(c)



[[1 1 1]
 [2 2 2]
 [3 3 3]]
[[1, 2, 3], [1, 2, 3], [1, 2, 3]]
[[1 2 3]
 [1 2 3]
 [1 2 3]]

 

posted @ 2018-10-17 11:46  cn_gzb  阅读(198)  评论(0编辑  收藏  举报