实验一

task1:

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// 现代C++标准库、算法库体验
// 本例用到以下内容:
// 1. 字符串string, 动态数组容器类vector、迭代器
// 2. 算法库:反转元素次序、旋转元素
// 3. 函数模板、const引用作为形参

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>

using namespace std;

// 声明
// 模板函数声明
template<typename T>
void output(const T &c);

// 普通函数声明
void test1();
void test2();
void test3();

int main() {
    cout << "测试1: \n";
    test1();

    cout << "\n测试2: \n";
    test2();

    cout << "\n测试3: \n";
    test3();
}

// 函数实现
// 输出容器对象c中的元素
template <typename T>
void output(const T &c) {
    for(auto &i: c)
        cout << i << " ";
    cout << endl;
}

// 测试1
// 组合使用算法库、迭代器、string反转字符串
void test1() {
    string s0{"0123456789"};
    cout << "s0 = " << s0 << endl;

    string s1{s0};
    reverse(s1.begin(), s1.end());  // 反转指定迭代器区间的元素
    cout << "s1 = " << s1 << endl;

    string s2{s0};
    reverse_copy(s0.begin(), s0.end(), s2.begin()); // 将指定迭代区间的元素拷贝到指定迭代器开始的目标区间,并且在复制过程中反转次序
    cout << "s2 = " << s2 << endl;
}

// 测试2
// 组合使用算法库、迭代器、vector反转动态数组对象vector内数据
void test2() {
    vector<int> v0{2, 0, 4, 9};
    cout << "v0: ";
    output(v0);

    vector<int> v1{v0};
    reverse(v1.begin(), v1.end());
    cout << "v1: ";
    output(v1);

    vector<int> v2{v0};
    reverse_copy(v0.begin(), v0.end(), v2.begin());
    cout << "v2: ";
    output(v2);
}

// 测试3
// 组合使用算法库、迭代器、vector实现元素旋转移位
void test3() {
    vector<int> v0{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
    cout << "v0: ";
    output(v0);

    vector<int> v1{v0};
    rotate(v1.begin(), v1.begin()+1, v1.end());  // 旋转指定迭代器区间[v1.begin(), v1.end())之间的数据项,旋转后从迭代器v1.begin()+1位置的数据项开始
    cout << "v1: ";
    output(v1);

    vector<int> v2{v0};
    rotate(v2.begin(), v2.begin()+2, v2.end());
    cout << "v2: ";
    output(v2);

    vector<int> v3{v0};
    rotate(v3.begin(), v3.end()-1, v3.end());
    cout << "v3: ";
    output(v3);

    vector<int> v4{v0};
    rotate(v4.begin(), v4.end()-2, v4.end());
    cout << "v4: ";
    output(v4);
}
![](https://img2024.cnblogs.com/blog/3534134/202410/3534134-20241015181258511-560175349.png)

task2:

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#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
#include <numeric>
#include <iomanip>

using namespace std;

// 函数声明
// 模板函数声明
template<typename T>
void output(const T &c);

// 普通函数声明
int rand_int_100();
void test1();
void test2();

int main() {
    cout << "测试1: \n";
    test1();

    cout << "\n测试2: \n";
    test2();
}

// 函数实现
// 输出容器对象c中的元素
template <typename T>
void output(const T &c) {
    for(auto &i: c)
        cout << i << " ";
    cout << endl;
}

// 返回[0, 100]区间内的一个随机整数
int rand_int_100() {
    return rand() % 101;
}

// 测试1
// sort对容器类对象指定迭代器区间进行赋值、排序
void test1() {
    vector<int> v0(10);  // 创建一个动态数组对象v0, 对象大小为10
    generate(v0.begin(), v0.end(), rand_int_100); // 产生[0, 100]之间的随机整数赋值给指定迭代器区间[v0.begin(), v0.end())内的每个数据项
    cout << "v0: ";
    output(v0);

    vector<int> v1{v0};
    sort(v1.begin(), v1.end()); // 对指定迭代器区间[v1.begin(), v1.end())内数据项进行升序排序
    cout << "v1: ";
    output(v1);

    vector<int> v2{v0};
    sort(v2.begin()+1, v2.end()-1); // 对指定迭代器区间[v1.begin()+1, v1.end()-1)内数据项进行升序排序
    cout << "v2: ";
    output(v2);
}

// 测试2
// 对容器类对象指定迭代器区间进行赋值、计算最大值/最小值/均值
void test2() {
    vector<int> v0(10);
    generate(v0.begin(), v0.end(), rand_int_100);
    cout << "v0: ";
    output(v0);

    auto iter1 = min_element(v0.begin(), v0.end());
    cout << "最小值: " << *iter1 << endl;

    auto iter2 = max_element(v0.begin(), v0.end());
    cout << "最大值: " << *iter2 << endl;

    auto ans = minmax_element(v0.begin(), v0.end());
    cout << "最小值: " << *(ans.first) << endl;
    cout << "最大值: " << *(ans.second) << endl;
    double avg1 = accumulate(v0.begin(), v0.end(), 0)/v0.size();
    cout << "均值: " << fixed << setprecision(2) << avg1 << endl;

    cout << endl;

    vector<int> v1{v0};
    cout << "v0: ";
    output(v0);
    sort(v1.begin(), v1.end());
    double avg2 = accumulate(v1.begin()+1, v1.end()-1, 0)/(v1.size()-2);
    cout << "去掉最大值、最小值之后,均值: " << avg2 << endl;
}
![](https://img2024.cnblogs.com/blog/3534134/202410/3534134-20241015181336671-1014150666.png)

task3:

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#include <iostream>
#include <string>
#include <algorithm> 
bool is_palindrome(std::string s); 
int main() {    
using namespace std;    
string s;     
while(cin >> s)  // 多组输入,直到按下Ctrl+Z后结束测试        
cout << boolalpha << is_palindrome(s) << endl;
} 
bool is_palindrome(std::string s)
{    
std::string s1{s};    
reverse(s1.begin(),s1.end());    
if(s1==s)    
return true;    
else    
return false;
}
![](https://img2024.cnblogs.com/blog/3534134/202410/3534134-20241015181429194-1262168212.png)

task4

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#include <iostream>
#include <string>
#include <algorithm>

std::string dec2n(int x, int n = 2);

int main() {
    using namespace std;

    int x;
    while(cin >> x) {
        cout << "十进制: " << x << endl;
        cout << "二进制: " << dec2n(x) << endl;
        cout << "八进制: " << dec2n(x, 8) << endl;
        cout << "十六进制: " << dec2n(x, 16) << endl << endl;
    }
}

std::string dec2n(int x,int n){
  std::string a = "";
    if (x == 0) 
    return "0";
    while (x > 0) {
        int b = x % n;
        if (b < 10) {
            a = char(b + '0') +a;
        } else {
            a = char(b - 10 + 'A') + a;
        }
        x /= n;
    }
    return a;

}![](https://img2024.cnblogs.com/blog/3534134/202410/3534134-20241015181501603-1902714077.png)

task5:

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#include<iostream>
#include<iomanip>
#include<string>

using namespace std;

int main(){
	string s("ABCDEFGHIJKLMNOPQRSTUVWXYZ");
	for(int i=0;i<27;i++){
		for(int j=0;j<26;j++){
			if(j==0){
				if(i==0){
					cout<<setw(2)<<" ";
				}
				else{
					cout<<setw(2)<<i;
				}
			}
			else{
				if(i==0){
					cout<<setw(2)<<char(s[j-1]+32);
				}
				else{
					cout<<setw(2)<<s[(j+i-1)%26];
				}
			}
		}
		cout<<endl;
	}
}

![](https://img2024.cnblogs.com/blog/3534134/202410/3534134-20241015181613683-1985926145.png)

task6

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#include <iostream>
#include <ctime>
#include <cstdlib>
#include<iomanip>
int main() {
    srand(static_cast<unsigned int>(time(nullptr)));
    int correctCount = 0;
    for (int i = 0; i < 10; i++) {
        int num1 = rand() % 10 + 1;
        int num2 = rand() % 10 + 1;
        int op = rand() % 4;
        int result;
        std::string operation;
        if (op == 0) {
            operation = " + ";
            result = num1 + num2;
        } else if (op == 1) {
            if (num1 < num2) {
                int temp = num1;
                num1 = num2;
                num2 = temp;
            }
            operation = " - ";
            result = num1 - num2;
        } else if (op == 2) {
            operation = " * ";
            result = num1 * num2;
        } else {
            if (num1 % num2!= 0) {
                i--;
                continue;
            }
            operation = " / ";
            result = num1 / num2;
        }
        std::cout << num1 << operation << num2 << " = ";
        int userAnswer;
        std::cin >> userAnswer;
        if (userAnswer == result) {
            correctCount++;
        }
    }
    double accuracy = static_cast<double>(correctCount) / 10 * 100;
    std::cout << "正确率: " << std::fixed << std::setprecision(2) << accuracy << "%" << std::endl;
    return 0;
}
![](https://img2024.cnblogs.com/blog/3534134/202410/3534134-20241015181811322-2127678571.png)
posted @ 2024-10-15 18:23  连跪也能称雄  阅读(13)  评论(0编辑  收藏  举报