vertx的Future设计

异步痛点

1.回调地狱(CallBack hell) ; 解决方式 Promise 或 Future

2.执行异步后的结果如何回调currentThread ; 解决方式 Context 设计

3.如何处理依赖多异步的result进行逻辑 ; 解决方案 CompositeFuture

JDK的lib库 Callable和Future 问题

Callable任务可以返回结果，返回的结果可以由Future对象取出,但是调用Future.get()会阻塞当前线程

public V get() throws InterruptedException, ExecutionException {
    int s = state;
    if (s <= COMPLETING)
        s = awaitDone(false, 0L);
    return report(s);
}


public V get(long timeout, TimeUnit unit)
    throws InterruptedException, ExecutionException, TimeoutException {
    if (unit == null)
        throw new NullPointerException();
    int s = state;
    if (s <= COMPLETING &&
        (s = awaitDone(true, unit.toNanos(timeout))) <= COMPLETING)
        throw new TimeoutException();
    return report(s);
}

 /**
 * 等待完成，或者中断、超时
 *
 * @param timed 定义了超时则为true
 * @param nanos 等待时间
 */
private int awaitDone(boolean timed, long nanos)
    throws InterruptedException {
    final long deadline = timed ? System.nanoTime() + nanos : 0L;
    WaitNode q = null;
    boolean queued = false;
    //轮询查看FutureTask的状态
    for (;;) {
        if (Thread.interrupted()) {//线程中断
            removeWaiter(q);
            throw new InterruptedException();
        }

        int s = state;
        if (s > COMPLETING) {//完成或取消状态
            if (q != null)
                q.thread = null;
            return s;
        }
        else if (s == COMPLETING)//正在set result,Thread “运行状态”进入到“就绪状态”
            Thread.yield();
        else if (q == null)
            q = new WaitNode();
        else if (!queued)
            queued = UNSAFE.compareAndSwapObject(this, waitersOffset,
                                                 q.next = waiters, q);
        else if (timed) {
            nanos = deadline - System.nanoTime();
            if (nanos <= 0L) {
                removeWaiter(q);
                return state;
            }
            LockSupport.parkNanos(this, nanos);
        }
        else
            LockSupport.park(this);
    }
}

 

vertx的Future设计

1. Future通过事件注册(EventHandler)回调方式,来解决Thread阻塞问题.

UML图:

 　 　

Futrue instances 采用FutureFactory生产，基于 SPI 机制:

public class FutureFactoryImpl implements FutureFactory {

  private static final SucceededFuture EMPTY = new SucceededFuture<>(null);

  /**
    * 创建FutureImpl 实例
    */
  public <T> Future<T> future() {
    return new FutureImpl<>();
  }

  /**
    * 返回一个常量 SucceededFuture 实例
    * result本身为null,　可以减少内存开销
    */
  public <T> Future<T> succeededFuture() {
    @SuppressWarnings("unchecked")
    Future<T> fut = EMPTY;
    return fut;
  }

  /**
    * 创建一个 SucceededFuture 实例
    */
  public <T> Future<T> succeededFuture(T result) {
    return new SucceededFuture<>(result);
  }

  /**
    * 创建一个 FailedFuture 实例
    */
  public <T> Future<T> failedFuture(Throwable t) {
    return new FailedFuture<>(t);
  }

  /**
    * 创建一个 FailedFuture 实例
    */
  public <T> Future<T> failureFuture(String failureMessage) {
    return new FailedFuture<>(failureMessage);
  }
}

 

多异步的result如何组合(并行变串行)

使用的CompositeFuture，来处理多异步结果组合问题:采用计数器(Counters)的方法来解决 wait 问题

public class CompositeFutureImpl implements CompositeFuture, Handler<AsyncResult<CompositeFuture>> {

  private final Future[] results;//定义数组
  
  private int count;//计数器
  
  private boolean completed;//是否完成
  
  private Throwable cause;//错误原因
  
  private Handler<AsyncResult<CompositeFuture>> handler;// 回调 eventHandler
  
  public static CompositeFuture all(Future<?>... results) {
    CompositeFutureImpl composite = new CompositeFutureImpl(results);//创建实例
    int len = results.length;　//获取 futures数组长度
    for (int i = 0; i < len; i++) {
      results[i].setHandler(ar -> {
        Handler<AsyncResult<CompositeFuture>> handler = null;
        if (ar.succeeded()) {
          synchronized (composite) { //添加内存屏障，防止并发问题
            composite.count++;　
            if (!composite.isComplete() && composite.count == len) {//所有future成功
              handler = composite.setCompleted(null);
            }
          }
        } else {
          synchronized (composite) {//添加内存屏障，防止并发问题
            if (!composite.isComplete()) {//任何一个失败就失败
              handler = composite.setCompleted(ar.cause());
            }
          }
        }
        if (handler != null) {//执行回调EventHandler
          handler.handle(composite);
        }
      });
    }
    if (len == 0) {//判断临界点
      composite.setCompleted(null);
    }
    return composite;
    }
}

public static CompositeFuture any(Future<?>... results) {
    CompositeFutureImpl composite = new CompositeFutureImpl(results);
    int len = results.length;
    for (int i = 0;i < len;i++) {
      results[i].setHandler(ar -> {
        Handler<AsyncResult<CompositeFuture>> handler = null;
        if (ar.succeeded()) {
          synchronized (composite) {
            if (!composite.isComplete()) {//任何一个成功
              handler = composite.setCompleted(null);
            }
          }
        } else {
          synchronized (composite) {
            composite.count++;
            if (!composite.isComplete() && composite.count == len) {//所有future失败
              handler = composite.setCompleted(ar.cause());
            }
          }
        }
        if (handler != null) {//执行回调EventHandler
          handler.handle(composite);
        }
      });
    }
    if (results.length == 0) {//判断临界点
      composite.setCompleted(null);
    }
    return composite;
}

private  static CompositeFuture join(Function<CompositeFuture, Throwable> pred, Future<?>... results) {
    CompositeFutureImpl composite = new CompositeFutureImpl(results);
    int len = results.length;
    for (int i = 0; i < len; i++) {
      results[i].setHandler(ar -> {
        Handler<AsyncResult<CompositeFuture>> handler = null;
        synchronized (composite) {
          composite.count++;
          if (!composite.isComplete() && composite.count == len) {//处理所有不管失败还是成功
            // Take decision here
            Throwable failure = pred.apply(composite);
            handler = composite.setCompleted(failure);
          }
        }
        if (handler != null) {
          handler.handle(composite);
        }
      });
    }
    if (len == 0) {//{//判断临界点
      composite.setCompleted(null);
    }
    return composite;
}

/**
  * 根据下标返回结果
  * /
public <T> T resultAt(int index) {
    return this.<T>future(index).result();
}
 

 

public interface CompositeFuture extends Future<CompositeFuture> {
    /**
      * 返回list Future.result()
      */
    default <T> List<T> list() {
        int size = size();
        ArrayList<T> list = new ArrayList<>(size);
        for (int index = 0;index < size;index++) {
          list.add(resultAt(index));
        }
        return list;
    }
}