BZOJ3682 : Phorni
后缀平衡树+线段树。
$O(1)$比较大小的标号法真是强大。
#include<cstdio> #include<cmath> #define N 300010 #define M 500010 using namespace std; typedef unsigned long long ll; const ll inf=1ULL<<63; const double A=0.8; ll tl[N],tr[N],tm[N]; int size[N],son[N][2],f[N],v[N],tot,root,id[N],cnt; char s[N],ch; inline void read(int&a){char c;while(!(((c=getchar())>='0')&&(c<='9')));a=c-'0';while(((c=getchar())>='0')&&(c<='9'))(a*=10)+=c-'0';} inline bool cmp(int a,int b){return s[a]==s[b]?tm[a-1]>tm[b-1]:s[a]>s[b];} int ins(int x,int p){ int b=cmp(p,v[x]); if(!son[x][b]){ son[x][b]=++tot;f[tot]=x;v[tot]=p; if(!b)tl[tot]=tl[x],tr[tot]=tm[x];else tl[tot]=tm[x],tr[tot]=tr[x]; tm[tot]=(tl[tot]+tr[tot])>>1; return tot; }else return ins(son[x][b],p); } void dfs(int x){ if(son[x][0])dfs(son[x][0]); id[++cnt]=x; if(son[x][1])dfs(son[x][1]); } int build(int fa,int l,int r,ll a,ll b){ int mid=(l+r)>>1,x=id[mid]; f[x]=fa;son[x][0]=son[x][1]=0;size[x]=1;tl[x]=a;tr[x]=b;tm[x]=(a+b)>>1; if(l==r)return x; if(l<mid)size[x]+=size[son[x][0]=build(x,l,mid-1,a,tm[x])]; if(r>mid)size[x]+=size[son[x][1]=build(x,mid+1,r,tm[x],b)]; return x; } inline int rebuild(int x){ cnt=0;dfs(x);return build(f[x],1,cnt,tl[x],tr[x]); } inline void insert(int p){ if(!root){root=tot=size[1]=1;v[1]=p;tr[1]=inf,tm[1]=inf>>1;return;} int x=ins(root,p); int deep=0,z=x;while(z)size[z]++,z=f[z],deep++; if(deep<log(tot)/log(1/A))return; while((double)size[son[x][0]]<A*size[x]&&(double)size[son[x][1]]<A*size[x])x=f[x]; if(!x)return; if(x==root){root=rebuild(x);return;} int y=f[x],b=son[y][1]==x,now=rebuild(x); son[y][b]=now; } int l[M<<1],r[M<<1],min[M<<1],seq[M],TOT; void build(int a,int b){ int x=++TOT; if(a==b){min[x]=a;return;} int mid=(a+b)>>1; l[x]=TOT+1;build(a,mid); r[x]=TOT+1;build(mid+1,b); min[x]=tm[seq[min[l[x]]]]<=tm[seq[min[r[x]]]]?min[l[x]]:min[r[x]]; } void change(int x,int a,int b,int c){ if(a==b)return; int mid=(a+b)>>1; if(c<=mid)change(l[x],a,mid,c);else change(r[x],mid+1,b,c); min[x]=tm[seq[min[l[x]]]]<=tm[seq[min[r[x]]]]?min[l[x]]:min[r[x]]; } int ask(int x,int a,int b,int c,int d){ if(c<=a&&b<=d)return min[x]; int mid=(a+b)>>1,i,j; if(d<=mid)return ask(l[x],a,mid,c,d); if(c>mid)return ask(r[x],mid+1,b,c,d); i=ask(l[x],a,mid,c,d),j=ask(r[x],mid+1,b,c,d); return tm[seq[i]]<=tm[seq[j]]?i:j; } int n,m,i,x,y,len,type,ans; int main(){ read(n);read(m);read(len);read(type); for(getchar(),i=1;i<=len;i++)s[len-i+1]=getchar(); for(i=1;i<=len;i++)insert(i); for(i=1;i<=n;i++)read(seq[i]); build(1,n); while(m--){ while(!(((ch=getchar())=='I')||(ch=='C')||(ch=='Q')));read(x); if(ch=='I')s[++len]=(x^ans*type)+'a',insert(len); if(ch=='C')read(seq[x]),change(1,1,n,x); if(ch=='Q')read(y),printf("%d\n",ans=ask(1,1,n,x,y)); } return 0; }