leetcode-----169. 多数元素

• 链接：https://leetcode-cn.com/problems/majority-element/

算法

时间复杂度：\(O(n)\)

代码

class Solution {
public:
    int majorityElement(vector<int>& nums) {
        int ans = nums[0], count = 1;
        for (int i = 1; i < nums.size(); ++i) {
            if (count == 0) ans = nums[i];
            if (nums[i] == ans) count += 1;
            else count -= 1;
        }
        return ans;
    }
};