实验4
#include <stdio.h> #define N 4 int main() { int a[N] = { 2, 0, 2, 2 }; char b[N] = { '2', '0', '2', '2' }; int i; printf("sizeof(int) = %d\n", sizeof(int)); printf("sizeof(char) = %d\n", sizeof(char)); printf("\n"); for (i = 0; i < N; ++i) printf("%p: %d\n", &a[i], a[i]); printf("\n"); for (i = 0; i < N; ++i) printf("%p: %c\n", &b[i], b[i]); printf("\n"); printf("a = %p\n", a); printf("b = %p\n", b); return 0; }
1.是连续存放的,占4个字节
2.不是连续存放,占1个字节
3.是
#include <stdio.h> #define N 2 #define M 3 int main() { int a[N][M] = { {1, 2, 3}, {4, 5, 6} }; char b[N][M] = { {'1', '2', '3'}, {'4', '5', '6'} }; int i, j; for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %d\n", &a[i][j], a[i][j]); printf("\n"); for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %c\n", &b[i][j], b[i][j]); return 0; }
1.不是,4个
2.不是,1个
#include <stdio.h> int days_of_year(int year, int month, int day); int main() { int year, month, day; int days; while (scanf_s("%d%d%d", &year, &month, &day) != 0) { days = days_of_year(year, month, day); printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days); } return 0; } int days_of_year(int year, int month, int day) { int m[13], i,s=0; for (i = 1; i <= 12; i++) { if (i == 4 || i == 6 || i == 9 || i == 11) m[i] = 30; if (i == 2) { if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) m[i] = 29; else m[i] = 28; } else m[i] = 31; } for (i = 1; i < month; i++) { s += m[i]; } return (s + day); }
#include <stdio.h> #define N 5 void input(int x[], int n); void output(int x[], int n); double average(int x[], int n); void sort(int x[], int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n", N); input(scores, N); printf("\n输出课程分数: \n"); output(scores, N); printf("\n课程分数处理: 计算均分、排序...\n"); ave = average(scores, N); sort(scores, N); printf("\n输出课程均分: %.2f\n", ave); printf("\n输出课程分数(高->低):\n"); output(scores, N); return 0; } void input(int x[], int n) { int i; for (i = 0; i < n; ++i) scanf_s("%d", &x[i]); } void output(int x[], int n) { int i; for (i = 0; i < n; ++i) printf("%d ", x[i]); printf("\n"); } double average(int x[], int n) { int i; double s = 0; for (i = 0; i < n; i++) { s += x[i]; } return (s / n); } void sort(int x[], int n) { int i,t,j; for (j = 1; j <= n * (n - 1) / 2; j++) { for (i = 0; i < n - 1; i++) { if (x[i] < x[i + 1]) { t = x[i + 1]; x[i + 1] = x[i]; x[i] = t; } } } }
#include <stdio.h> void dec2n(int x, int n); // 函数声明 int main() { int x; printf("输入一个十进制整数: "); scanf_s("%d", &x); dec2n(x, 2); dec2n(x, 8); dec2n(x, 16); return 0; } void dec2n(int x, int n) { int i, j; int a[20]; for (i = 0; i < 20; i++) { if (x / n != 0) { a[i] = x % n; x = x / n; } else { a[i] = x; break; } } for (j = i; j >= 0; j--) { if (n == 16 && a[j] >= 10) { switch (a[j] % 10) { case 0:printf("A"); break; case 1:printf("B"); break; case 2:printf("C"); break; case 3:printf("D"); break; case 4:printf("E"); break; case 5:printf("F"); break; } } else printf("%d", a[j]); } printf("\n"); }
#include<stdio.h> #include<stdlib.h> #define N 50 void juzhen(int x[N][N], int n); int main() { int n, l,c,a[N][N]; printf("Enter n:"); while (scanf_s("%d", &n) != 0) { juzhen(a, n); for (l = 1; l <= n; l++) { for (c = 1; c <= n; c++) { printf("%d ", a[l][c]); } printf("\n"); } printf("\nEnter n:"); } return 0; } void juzhen(int x[N][N], int n) { int i, j; for (i = 1; i <= n; i++) { for (j = 1; j <= n; j++) { if (j <= i) x[i][j] = j; else x[i][j] = i; } } }
#include <stdio.h> #define N 80 int main() { int i, j; char t; char views1[N] = "hey, c, i hate u."; char views2[N] = "hey, c, i love u."; printf("original views:\nviews1: "); for (i = 0; i < N; i++) printf("%c", views1[i]); printf("\nviews2: "); for (i = 0; i < N; i++) printf("%c", views2[i]); printf("\n\nswapping...\n\nviews1: "); for (i = 0; i < N; i++) { if (views1[i] == views2[i]) continue; else { t = views1[i]; views1[i] = views2[i]; views2[i] = t; } } for (i = 0; i < N; i++) printf("%c", views1[i]); printf("\nviews2: "); for (i = 0; i < N; i++) printf("%c", views2[i]); return 0; }
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <string.h> #define N 5 #define M 20 void bubble_sort(char str[][M], int n); int main() { char name[][M] = { "Bob", "Bill", "Joseph", "Taylor", "George" }; int i; printf("输出初始名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); printf("\n排序中...\n"); bubble_sort(name, N); printf("\n按字典序输出名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); return 0; } void bubble_sort(char str[][M], int n) { int i, j,k; char a[10]; for (i = 1; i < n * (n - 1) / 2; i++) { for (j = 0; j < N - 1; j++) { if (str[j][0] == str[j + 1][0]) { for (k = 1; k < M; k++) { if (str[j][1] > str[j + 1][1]) { strcpy(a, str[j + 1]); strcpy(str[j + 1], str[j]); strcpy(str[j], a); } } } else if (str[j][0] > str[j + 1][0]) { strcpy(a, str[j + 1]); strcpy(str[j + 1], str[j]); strcpy(str[j], a); } } } }