FZU 2104 Floor problem (水题)

 Problem 2104 Floor problem

Accept: 546    Submit: 615
Time Limit: 1000 mSec    Memory Limit : 32768 KB

 Problem Description

In this problem, we have f(n,x)=Floor[n/x]. Here Floor[x] is the biggest integer such that no larger than x. For example, Floor[1.1]=Floor[1.9]=1, Floor[2.0]=2.

 

You are given 3 positive integers n, L and R. Print the result of f(n,L)+f(n,L+1)+...+f(n,R), please.

 Input

The first line of the input contains an integer T (T≤100), indicating the number of test cases.

Then T cases, for any case, only 3 integers n, L and R (1≤n, L, R≤10,000, L≤R).

 Output

For each test case, print the result of f(n,L)+f(n,L+1)+...+f(n,R) in a single line.

 Sample Input

3
1 2 3
100 2 100
100 3 100

 Sample Output

0
382
332

 Source

“高教社杯”第三届福建省大学生程序设计竞赛

 

注意int本来是向下取整即可

 1 #include<cstdio>
 2 #include<cmath>
 3 #include<cstring>
 4 #include<stdlib.h>
 5 #include<algorithm>
 6 using namespace std;
 7 int main()
 8 {
 9     //freopen("in.txt","r",stdin);
10     int kase;
11     scanf("%d",&kase);
12     while(kase--)
13     {
14         int n,l,r;
15         int sum=0;
16         scanf("%d %d %d",&n,&l,&r);
17         for(int i=l;i<=r;i++)
18             sum+=n/i;
19         printf("%d\n",sum);
20     }
21     return 0;
22 }
View Code

 

posted @ 2014-08-19 15:52  Cliff Chen  阅读(146)  评论(0编辑  收藏  举报