java - java调用python3接口导致的unicode乱码问题

因为python传json默认是unicode,所以经常会碰到java调用python接口返回unicode乱码问题。

类似:

\u8d34\u5427\u5373\u767e\u5ea6\u8d34\u5427\uff0c\u662f\u767e\u5ea6\u65d7\u4e0b\u72ec\u7acb\u54c1\u724c\uff0c\u5168\u7403\u6700\u5927\u7684\u4e2d\u6587\u793e\u533a\u3002

 

用下面的方法可以直接转换返回的json字符串,亲测好用-。-

 

来源:https://blog.csdn.net/a214919447/article/details/54601832

 

// unicode -> 汉字
    public static String decodeUnicode(String theString) {
        char aChar;
        int len = theString.length();
        StringBuffer outBuffer = new StringBuffer(len);
        for (int x = 0; x < len;) {
            aChar = theString.charAt(x++);
            if (aChar == '\\') {
                aChar = theString.charAt(x++);
                if (aChar == 'u') {
                    // Read the xxxx
                    int value = 0;
                    for (int i = 0; i < 4; i++) {
                        aChar = theString.charAt(x++);
                        switch (aChar) {
                            case '0':
                            case '1':
                            case '2':
                            case '3':
                            case '4':
                            case '5':
                            case '6':
                            case '7':
                            case '8':
                            case '9':
                                value = (value << 4) + aChar - '0';
                                break;
                            case 'a':
                            case 'b':
                            case 'c':
                            case 'd':
                            case 'e':
                            case 'f':
                                value = (value << 4) + 10 + aChar - 'a';
                                break;
                            case 'A':
                            case 'B':
                            case 'C':
                            case 'D':
                            case 'E':
                            case 'F':
                                value = (value << 4) + 10 + aChar - 'A';
                                break;
                            default:
                                throw new IllegalArgumentException(
                                        "Malformed   \\uxxxx   encoding.");
                        }

                    }
                    outBuffer.append((char) value);
                } else {
                    if (aChar == 't')
                        aChar = '\t';
                    else if (aChar == 'r')
                        aChar = '\r';
                    else if (aChar == 'n')
                        aChar = '\n';
                    else if (aChar == 'f')
                        aChar = '\f';
                    outBuffer.append(aChar);
                }
            } else
                outBuffer.append(aChar);
        }
        return outBuffer.toString();
    }

 

posted @ 2020-11-09 15:31  不咬人的兔子  阅读(631)  评论(0编辑  收藏  举报