牛客 136G-指纹锁 set容器重载

136G-指纹锁

题意：

　　　设计一个容器，支持插入x，若与容器中的值最小相差为k，则自动忽略。删除操作，把与x相差为k的值都从容器中删除。查询操作，问容器中有没有和x相差为k的数值。

思路：

　　一个stl中的set 加上cmp结构体重载就搞定了。神奇。

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <string>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <list>
#include <cstdlib>
#include <iterator>
#include <cmath>
#include <iomanip>
#include <bitset>
#include <cctype>
using namespace std;
//#pragma GCC optimize(3)
//#pragma comment(linker, "/STACK:102400000,102400000")  //c++
#define lson (l , mid , rt << 1)
#define rson (mid + 1 , r , rt << 1 | 1)
#define debug(x) cerr << #x << " = " << x << "\n";
#define pb push_back
#define pq priority_queue



typedef long long ll;
typedef unsigned long long ull;

typedef pair<ll ,ll > pll;
typedef pair<int ,int > pii;
typedef pair<int ,pii> p3;
//priority_queue<int> q;//这是一个大根堆q
//priority_queue<int,vector<int>,greater<int> >q;//这是一个小根堆q
#define fi first
#define se second
//#define endl '\n'

#define OKC ios::sync_with_stdio(false);cin.tie(0)
#define FT(A,B,C) for(int A=B;A <= C;++A)  //用来压行
#define REP(i , j , k)  for(int i = j ; i <  k ; ++i)
//priority_queue<int ,vector<int>, greater<int> >que;

const ll mos = 0x7FFFFFFFLL;  //2147483647
const ll nmos = 0x80000000LL;  //-2147483648
const int inf = 0x3f3f3f3f;
const ll inff = 0x3f3f3f3f3f3f3f3fLL; //18
const double PI=acos(-1.0);

template<typename T>
inline T read(T&x){
    x=0;int f=0;char ch=getchar();
    while (ch<'0'||ch>'9') f|=(ch=='-'),ch=getchar();
    while (ch>='0'&&ch<='9') x=x*10+ch-'0',ch=getchar();
    return x=f?-x:x;
}
// #define _DEBUG;         //*//
#ifdef _DEBUG
freopen("input", "r", stdin);
// freopen("output.txt", "w", stdout);
#endif
/*-----------------------show time----------------------*/
                int n,k;        char str[10];
                struct cmp
                {   
                    bool operator()(int a,int b)const {
                        if(abs(a-b) <= k)return false;
                        return a < b;
                    }
                };
                set<int,cmp>s;
int  main(){
                scanf("%d%d", &n, &k);
                for(int i=1; i<=n; i++){
                    int x;  scanf("%s%d", str, &x);
                    if(str[0] == 'a'){
                        if(s.find(x) == s.end()) s.insert(x);    
                    }
                    else if(str[0] == 'q'){
                        if(s.find(x) == s.end()) puts("No");
                        else puts("Yes");
                    }
                    else {
                        while(s.find(x) != s.end()){
                            s.erase(x);
                        }
                    }
                }
                return 0;
}