jquery 中post 、get的同步问题,从外部获取返回数据
解决方法1:
在全局设置:
- $.ajaxSetup({
- async : false
- });
- $.ajaxSetup({
- async : false
- });
然后再使用post或get方法
- $.get("register/RegisterState", {test : 12}, function(data, status) {
- if (status == "success") {
- data = eval("(" + data + ")");
- aDataSet = data;
- alert("data is " + aDataSet);
- } else {
- alert("wrong");
- }
- });
- $.get("register/RegisterState", {test : 12}, function(data, status) {
- if (status == "success") {
- data = eval("(" + data + ")");
- aDataSet = data;
- alert("data is " + aDataSet);
- } else {
- alert("wrong");
- }
- });
解决方法2:
直接使用$.ajax,如
- $.ajax({
- type : "post",
- url : "register/RegisterState",
- data : "test=" + test,
- async : false,
- success : function(data){
- data = eval("(" + data + ")");
- aDataSet = data;
- }
- });