C++走向远洋——66(十五周阅读程序)

*/
 * Copyright (c) 2016,烟台大学计算机与控制工程学院
 * All rights reserved.
 * 文件名:text.cpp
 * 作者:常轩
 * 微信公众号:Worldhello
 * 完成日期:2016年6月8日
 * 版本号:V1.0
 * 问题描述:
 * 程序输入:无
 * 程序输出:见运行结果
 */
#include <string>
#include <set>
#include <iterator>
#include <iostream>
using namespace std;
int main()
{
    set <string> strset;
    strset.insert("cantaloupes");
    strset.insert("grapes");
    strset.insert("apple");
    strset.insert("orange");
    strset.insert("banana");
    strset.insert("grapes");
    copy(strset.begin(), strset.end(), ostream_iterator<string>(cout, " "));
    cout << endl;
    return 0;
}


#include <functional>
#include <numeric>
#include <vector>
#include <iostream>
using namespace std;
int main()
{
    vector<int> v(5);
    for (int i = 0; i < 5; i++)
        v[i] = i + 1;
    int sum = accumulate(v.begin(), v.end(), 0);
    cout << "Sum of values == " << sum << endl;
    int product = accumulate(v.begin(), v.end(), 1, multiplies<long>());
    cout << "Product of values == " << product << endl;
    return 0;
}


#include <algorithm>
#include <functional>
#include <vector>
#include <iostream>
#include <numeric>
#include <iterator>
using namespace std;
int main()
{
    int a[] = {1,4,7,2,5,8};
    int b[] = {1,2,3,3,2,1};
    const int ASZ = sizeof a / sizeof a[0];
    const int BSZ = sizeof b / sizeof b[0];
    ostream_iterator<int> out(cout,"  ");
    copy(a, a + ASZ, out);
    cout<<endl;
    copy(b, b + BSZ, out);
    cout<<endl;
    int r = accumulate(a, a + ASZ, 0);
    cout << "accumulate 1: " << r << endl;
    // Should produce the same result:
    r = accumulate(b, b + BSZ, 0, plus<int>());
    cout << "accumulate 2: " << r << endl;
    r = inner_product(a, a + ASZ, b, 0);
    // 或  r = inner_product(a, a + ASZ, b, 0, plus<int>(), multiplies<int>());
    cout << "inner_product : " << r << endl;
    int* it = partial_sum(a, a + ASZ, b);
    // 或 int* it = partial_sum(a, a + ASZ, b, plus<int>());
    copy(b, it, out);
    cout<<endl;
    it = adjacent_difference(a, a + ASZ, b);
    // 或 it = adjacent_difference(a, a + ASZ, b, minus<int>());
    copy(b, it, out);
    cout<<endl;
    return 0;
}



posted @ 2016-06-08 15:51  壹言  阅读(129)  评论(0编辑  收藏  举报