用Java8把List转为Map
1 import com.yang.test.User; 2 3 import javax.jws.soap.SOAPBinding; 4 import java.util.*; 5 import java.util.function.Function; 6 import java.util.stream.Collectors; 7 8 public class Main { 9 10 public static void main(String[] args) { 11 12 List<User> userlist = new ArrayList<>(); 13 for (int i = 0; i <10; i++) { 14 15 userlist.add(new User("张三"+i,i)); 16 } 17 System.out.println(getAllages(userlist).size()); 18 19 System.out.println(getUser2Map(userlist)); 20 21 System.out.println(getUser2MapUser(userlist)); 22 23 System.out.println(getUser2MapUser2(userlist)); 24 25 System.out.println(getUser2MapUser3(userlist)); 26 27 } 28 29 public static List<Integer> getAllages(List<User>userlist){ 30 return userlist.stream().map(user -> user.getAge()).collect(Collectors.toList()); 31 } 32 33 public static Map<Integer,String> getUser2Map(List<User>userlist){ 34 35 return userlist.stream().collect(Collectors.toMap(User::getAge,User::getName)); 36 } 37 38 public static Map<Integer,User> getUser2MapUser(List<User>userlist){ 39 40 return userlist.stream().collect(Collectors.toMap(User::getAge,User-> User)); 41 } 42 43 /** 44 * 比较优雅的写法是这样的 45 * @param userlist 46 * @return 47 */ 48 public static Map<Integer,User> getUser2MapUser2(List<User>userlist){ 49 50 return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity())); 51 } 52 53 /** 54 * 重复key的情况下 简单的使用后者覆盖前者的 55 */ 56 public static Map<Integer,User> getUser2MapUser3(List<User>userlist){ 57 58 return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity(),(key1,key2)->key2)); 59 } 60 61 /** 62 *指定map的具体实现 63 * @param userlist 64 * @return 65 */ 66 public static Map<Integer,User> getUser2MapUser4(List<User>userlist){ 67 68 return userlist.stream().collect(Collectors.toMap(User::getAge, Function.identity(),(key1,key2)->key2, LinkedHashMap::new)); 69 } 70 }