dynamic关键字的使用

https://www.newtonsoft.com/json/help/html/T_Newtonsoft_Json_JsonConvert.htm

在使用DeserializeObject函数进行转换的时候，会自动处理，如果和T匹配，就会转换好。

如果类型不匹配，也不会报错的。

  public class Person
        {
            public string Id { get; set; }
            public string FirstName { get; set; }
            public string LastName { get; set; }
            public string Email { get; set; }
        }
        public class People
        {
            public string Gender { get; set; }
        }

        /// <summary>
        /// 生成json字符串
        /// </summary>
        [Test]
        public void Test14()
        {
            Person person = new Person
            {
                Id = "10232",
                FirstName = "Chuck",
                LastName = "Lu",
                Email = "chuck.lu@qq.com"
            };
            string str = JsonConvert.SerializeObject(person);
            Console.WriteLine(str);
        }
        
        /// <summary>
        /// 测试dynamic关键字的使用
        /// </summary>
        [Test]
        public void Test15()
        {
            string str = "{\"Id\":\"10232\",\"FirstName\":\"Chuck\",\"LastName\":\"Lu\",\"Email\":\"chuck.lu@qq.com\"}";
            var temp = JsonConvert.DeserializeObject<dynamic>(str);
            //这里都是硬编码调用的
            Console.WriteLine($@"{temp.Id} {temp.Id.GetType()}");
            Console.WriteLine($@"{temp.FirstName} {temp.FirstName.GetType()}");
            Console.WriteLine($@"{temp.LastName} {temp.LastName.GetType()}");
            Console.WriteLine($@"{temp.Email} {temp.Email.GetType()}");
            Console.WriteLine($@"{temp.Gender} {temp.Gender?.GetType()}");  //这里的Gender是null
            Console.WriteLine();

            var person = JsonConvert.DeserializeObject<Person>(str);
            Console.WriteLine(person.GetType());
            Console.WriteLine($@"{person.Id} {person.Id.GetType()}");
            Console.WriteLine($@"{person.FirstName} {person.FirstName.GetType()}");
            Console.WriteLine($@"{person.LastName} {person.LastName.GetType()}");
            Console.WriteLine($@"{person.Email} {person.Email.GetType()}");

            Console.WriteLine();
            var people = JsonConvert.DeserializeObject<People>(str);
            Console.WriteLine(people.GetType());
        }