Evaluate: lim x → 0 [1/x^2 - 1/sin^2x] 高等数学

Evaluate: lim x → 0 [1/x^2 - 1/sin^2x]

L = lim x → 0 [1/x2 - 1/sin2x]. [∞ – ∞] formRead more on Sarthaks.com - https://www.sarthaks.com/354486/evaluate-lim-x-0-1-x-2-1-sin-2x
 
 
 
 
 
 
posted @ 2022-08-23 14:46  ChuckLu  阅读(44)  评论(0)  编辑  收藏  举报