237. Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = [4,5,1,9], which looks like following:

Example 1:

Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.

Example 2:

Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.

Note:

The linked list will have at least two elements.
All of the nodes' values will be unique.
The given node will not be the tail and it will always be a valid node of the linked list.
Do not return anything from your function.

刚开始题目都没看懂，后来看了discuss才知道，题目想要做什么。

给定链表中的一个结点，把这个结点删除。因为只是给定了结点，并没有链表的head。

所以，处理方式是，将结点的值，往前移动，然后删除最后一个结点。

public void DeleteNode(ListNode node)
        {
            ListNode nodePrev = node;
            while (node.next != null)
            {
                node.val = node.next.val;
                nodePrev = node;
                node = node.next;
            }

            nodePrev.next = null;
        }