|
Problem Description
Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X.
|
|
Input
There are many cases. Every data case is described as followed: In the first line there are three integers L, N, M, in the second line there are L integers represent the sequence A, in the third line there are N integers represent the sequences B, in the forth line there are M integers represent the sequence C. In the fifth line there is an integer S represents there are S integers X to be calculated. 1<=L, N, M<=500, 1<=S<=1000. all the integers are 32-integers.
|
|
Output
For each case, firstly you have to print the case number as the form "Case d:", then for the S queries, you calculate if the formula can be satisfied or not. If satisfied, you print "YES", otherwise print "NO".
|
|
Sample Input
3 3 3 1 2 3 1 2 3 1 2 3 3 1 4 10 |
|
Sample Output
Case 1: NO YES NO |
|
Code
1 #include <stdio.h> 2 #include <stdlib.h> 3 #define N 500 4 int a[N + 5], b[N + 5], c[N + 5], sumAB[N * N + 5]; 5 int compare(const void *a, const void *b) 6 { 7 return *(int*)a - *(int*)b; 8 } 9 void main() 10 { 11 int countA, countB, countC, countAB, countX; 12 int i, j, x, target; 13 int min, max, mid; 14 int result, n; 15 n = 1; 16 while (scanf("%d %d %d", &countA, &countB, &countC) != EOF) 17 { 18 for (i = 0; i < countA; i++) 19 scanf("%d", &a[i]); 20 for (i = 0; i < countB; i++) 21 scanf("%d", &b[i]); 22 for (i = 0; i < countC; i++) 23 scanf("%d", &c[i]); 24 for (i = 0; i < countA; i++) 25 for (j = 0; j < countB; j++) 26 sumAB[i * countB + j] = a[i] + b[j]; 27 countAB = countA * countB; 28 qsort(sumAB, countAB, sizeof(int), compare); 29 scanf("%d", &countX); 30 for (i = 0; i < countX; i++) 31 { 32 scanf("%d", &x); 33 for (j = 0; j < countC; j++) 34 { 35 target = x - c[j]; 36 result = 0; 37 min = 0; 38 max = countAB - 1; 39 while (min <= max) 40 { 41 mid = (min + max) / 2; 42 if (sumAB[mid] == target) 43 { 44 result = 1; 45 break; 46 } 47 else if (sumAB[mid] > target) 48 max = mid - 1; 49 else 50 min = mid + 1; 51 } 52 if (result == 1) 53 break; 54 } 55 if (i == 0) 56 printf("Case %d:\n", n++); 57 if (result) 58 printf("YES\n"); 59 else 60 printf("NO\n"); 61 } 62 } 63 }
|
|
Key Points
Firstly of all, I should be careful. I take a whole afternoon to find the fault which is missing the ":".
Secondly, I should proficient in the binsearch algorithm, whose range is [], and the condition is ≥, and u must add -1 or +1.
Thirdly, in C, u can only use qsort. and if u want use the function, u must add the head file "#include <stdlib.h>", and the "compare" function.
Fourthly, if u want use function, such strcpy, u should add "#include <string.h>", which is belong to C. And if u want use the type of "string", u should add "#include <string> using namespace std;". Those head files are really different.
Last but not the least, if u want debug, u can remember those short key, likes Ctrl+F10, which means u can run until the cursor, Shift+F5, which means stop.
|
|
Recommend
威士忌
|
