SQL使用IN参量不能超过1000的表现形式以及解决办法
如果出现这个错误说明你传的参量是超过了一千个值;列如,你拼接了1001个id;
如何解决那,我这里提供两种方法:
1.每1000条加一个or in
列:
原:select p.* from t_premium p where p.premium_id in ('0','1'........,'1000',......'2000');
现:select p.* from t_premium p where p.premium_id in ('0','1'......‘999’)or in (’1000',......'1999');
如何实现那?
看下边
1 public static void main(String[] agrs) throws Exception { 2 StringBuffer thirdPartyPayId=new StringBuffer(); 3 for (int j = 0; j < 20; j++) { 4 if((j%10) == 0 && j > 1){ 5 thirdPartyPayId.deleteCharAt(thirdPartyPayId.length() -1); 6 thirdPartyPayId.append(") OR " + "info.third_party_pay_id" + " IN ('" + j + "',"); 7 }else{ 8 thirdPartyPayId.append("'").append(j).append("',"); 9 } 10 } 11 thirdPartyPayId.deleteCharAt(thirdPartyPayId.length() -1); 12 System.out.println(thirdPartyPayId.toString()); 13 }
我这里用j代替了循环的"info.third_party_pay_id" ,兄弟们用的时候可以遍历自己的list,获取参量;
thirdPartyPayId.deleteCharAt(thirdPartyPayId.length() -1):去掉多余的标点符号,不能省;
SELECT DISTINCT
nvl(info.apply_policy_no,'无') applyPolicyNo
FROM T_THIRD_PARTY_PAY_INFO info,t_department_define o
WHERE info.department_code = o.internal_department_code(+)
AND (info.third_party_pay_id IN ($thirdPartyPayId$ ))
AND info.FLAG = '2'
注:1.这种方式效率很慢;数据量小的话也就无所谓;数据量大的话不建议使用;
2.()这两个括号必须要,因为(+)这个不能和in, not in 一起使用,但是因为
2.传递的参量转换成一个sql查询
SELECT DISTINCT
nvl(info.apply_policy_no,'无') applyPolicyNo
FROM T_THIRD_PARTY_PAY_INFO info,t_department_define o
WHERE info.department_code = o.internal_department_code(+)
AND info.third_party_pay_id IN (
SELECT
sd.third_party_pay_id
FROM T_SOURCE_DOCUMENT sd,t_voucher v
WHERE sd.VOUCHER_ID = v.VOUCHER_ID and v.voucher_code=#voucherCode#
AND sd.third_party_pay_id IS NOT NULL
and v.CANCEL_STATUS != '2'
)
AND info.FLAG = '2'
就是说你获取参量的那个查询sql放进来;
后记:应该还有join以及exists两种思路。但用起来感觉所锁定目标不太清晰。故没做考量;