摘要: assume cs:code code segment main: mov ax,0020h mov ds,ax ;指定段地址0200h mov dx,0h mov cx,003fh s: mov [dx],dx inc dx loop s mov ax,4c00h int 21h code end 阅读全文
posted @ 2019-09-12 13:16 东坡肉肉君 阅读(622) 评论(0) 推荐(0) 编辑