[LeetCode]题解（python）：114-Flatten Binary Tree to Linked List

题目来源：

　　https://leetcode.com/problems/flatten-binary-tree-to-linked-list/

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题意分析：

　　给出一个二叉树，将这个二叉树变成一个单链形式。

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题目思路：

　　递归的思想，先将根节点连接左子树，然后再连接右子树。

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代码（python）：

　　

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def flatten(self, root):
        """
        :type root: TreeNode
        :rtype: void Do not return anything, modify root in-place instead.
        """
        if root == None:
            return
        if root.left == None and root.right == None:
            return
        self.flatten(root.left);self.flatten(root.right)
        tmp = root.right
        root.right = root.left
        root.left = None
        while root.right:
            root = root.right
        root.right = tmp