[转] Lodash常用API笔记
原生用法
直接使用的API
_.reject
根据条件去除某个元素。
var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
var bar = _.reject(foo, ['id', 0])
//bar = [{id: 1, name: "bbb", age: 25}]
_.pick
根据第二个参数的key的数组,筛选第一个参数中的值并返回
var foo = {id: 0, name: "aaa", age: 33}
var bar = _.pick(foo, ['name', 'age'])
//bar = {name: "aaa", age: 33}
_.keys
返回object中的所有key
var foo = {id: 0, name: "aaa", age: 33}
var bar = _.keys(foo)
//bar = ['id', 'name', 'age']
_.cloneDeep
深度拷贝,这个不用多说了吧,js中基础类型以外的类型,都会默认拷贝备份var bar = _.cloneDeep(foo)
_.find
查找数组
var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
var bar = _.find(foo, ['id', 0])
//bar = {id: 0, name: "aaa", age: 33}
注意一下如果没找到的话,会返回undefined,要处理一下
_.keyBy
以某个属性为键,将数组转为对象
var foo = var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
var bar = _.keyBy(foo, 'name')
//bar = {
// aaa: {id: 0, name: "aaa", age: 33},
// bbb: {id: 1, name: "bbb", age: 25}
//}
_.filter
根据条件过滤出符合条件的元素,返回新数组
var foo = var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
var bar = _.filter(foo, ['name', "aaa"])
//bar = {
// aaa: {id: 0, name: "aaa", age: 33}
//}
_.map
从集合中挑出一个key,将其值作为数组返回
var foo = var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
var bar = _.map(foo, 'name')
//bar = ["aaa", "bbb"]
_.max/_.min/_.sum
数组中最大值、最小值、数组求和
var foo = [1, 2, 3, 4]
var bar = _.max(foo)
//bar = 4
bar = _.min(foo)
//bar = 1
bar = _.sum(foo)
//bar = 10
_.pad/_.padStart/_.padEnd
在两端、开头、末尾补齐字符
var foo = "helloworld"
var bar = _.pad(foo, 14, '-')
//bar = --helloworld--
bar = _.padStart(foo, 14, '-')
//bar = ----helloworld
bar = _.padEnd(foo, 14, '-')
//bar = helloworld----
组合用法
如果说上面是基础技能,那么下面奉上几个炫酷的组合技:
选出json数组中id最大的一项
var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
var bar = _.find(foo, ['id', _.max(_.map(foo, 'id'))])
// bar = {id: 1, name: "bbb", age: 25}
ps:也可以用maxBy某个key来代替
更新json数组中某一项的值
var foo = [
{id: 0, name: "aaa", age: 33},
{id: 1, name: "bbb", age: 25}
]
let list = _.keyBy(foo, 'id')
list[0].name = "ccc"
var bar = _.map(list)
// bar = [
// {id: 0, name: "ccc", age: 33},
// {id: 1, name: "bbb", age: 25}
//]