[LeetCode] ZigZag Conversion
The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)
should return "PAHNAPLSIIGYIR"
.
找到间隔相邻的规律,O(n)的时间可以完成
1 class Solution { 2 private: 3 int step[2]; 4 public: 5 string convert(string s, int nRows) { 6 // Start typing your C/C++ solution below 7 // DO NOT write int main() function 8 int steps = 2 * nRows - 2; 9 10 string ret(s); 11 int retSize = 0; 12 for(int i = 0; i < nRows; i++) 13 { 14 int num = nRows - (i + 1) + nRows - (i + 1) - 1; 15 num++; 16 step[0] = num; 17 if (step[0] == 0) 18 step[0] = steps; 19 step[1] = steps - num; 20 if (step[1] == 0) 21 step[1] = steps; 22 23 int j = i; 24 int index = 0; 25 while(j < s.size()) 26 { 27 ret[retSize++] = s[j]; 28 if (j == j + step[index]) 29 break; 30 j = j + step[index]; 31 index = 1 - index; 32 } 33 } 34 35 return ret; 36 } 37 };