[LeetCode] Unique Paths II
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1
and 0
respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is 2
.
Note: m and n will be at most 100.
同上题,稍作修改。
1 class Solution { 2 public: 3 int uniquePathsWithObstacles(vector<vector<int> > &obstacleGrid) { 4 // Start typing your C/C++ solution below 5 // DO NOT write int main() function 6 vector<vector<int> > f(obstacleGrid.size(), vector<int>(obstacleGrid[0].size())); 7 8 f[0][0] = obstacleGrid[0][0] == 1 ? 0 : 1; 9 for(int i = 1; i < f.size(); i++) 10 f[i][0] = obstacleGrid[i][0] == 1 ? 0 : f[i-1][0]; 11 12 for(int i = 1; i < f[0].size(); i++) 13 f[0][i] = obstacleGrid[0][i] == 1 ? 0 : f[0][i-1]; 14 15 for(int i = 1; i < f.size(); i++) 16 for(int j = 1; j < f[i].size(); j++) 17 f[i][j] = obstacleGrid[i][j] == 1 ? 0 : f[i-1][j] + f[i][j-1]; 18 19 return f[f.size()-1][f[0].size()-1]; 20 } 21 };