[LeetCode&Python] Problem 844. Backspace String Compare
Given two strings S
and T
, return if they are equal when both are typed into empty text editors. #
means a backspace character.
Example 1:
Input: S = "ab#c", T = "ad#c"
Output: true
Explanation: Both S and T become "ac".
Example 2:
Input: S = "ab##", T = "c#d#"
Output: true
Explanation: Both S and T become "".
Example 3:
Input: S = "a##c", T = "#a#c"
Output: true
Explanation: Both S and T become "c".
Example 4:
Input: S = "a#c", T = "b"
Output: false
Explanation: S becomes "c" while T becomes "b".
Note:
1 <= S.length <= 200
1 <= T.length <= 200
S
andT
only contain lowercase letters and'#'
characters.
Follow up:
- Can you solve it in
O(N)
time andO(1)
space?
class Solution(object): def backspaceCompare(self, S, T): """ :type S: str :type T: str :rtype: bool """ Sr=[] i=0 while i<len(S): if S[i]=='#': if Sr: Sr.pop() else: Sr.append(S[i]) i+=1 Tr=[] i=0 while i<len(T): if T[i]=='#': if Tr: Tr.pop() else: Tr.append(T[i]) i+=1 return Tr==Sr