删除dom空元素方法：
Js:
<html>
<head>
</head>
<body>
<div id="test"><span><imgs/></span></div>
</body>
</html>
<script src="http://libs.baidu.com/jquery/2.0.0/jquery.min.js"></script>
<script>
var dom = document.getElementById("test");
var widthTraversal = function(obj,result){
var stack = [];
stack.push(obj);
while(stack.length){
var item = stack.shift();
result.push(item);
var childs = item.children;
if(childs){
for(var i = 0; i < childs.length; i++){
stack.push(childs[i]);
}
}
}
}
var result1 = [];
widthTraversal(dom, result1);
for (var x = result1.length - 1; x >= 0; x--) {
var item = result1[x];
if (item.children.length == 0 && item.innerHTML == "" && item.tagName != "IMG") {
item.parentNode.removeChild(item);
}
}
console.log(result1);
console.log($("#test").html());
</script>
Jquery:
<html>
<head>
</head>
<body>
<div id="test">
<span>
<div>
</div>
</span>111
</div>
</body>
</html>
<script src="http://libs.baidu.com/jquery/2.0.0/jquery.min.js"></script>
<script>
var str = $("#test").html();
var dom = $("<div>" + str + "</div>")[0];
var widthTraversal = function (obj, result) {
var stack = [];
stack.push(obj);
while (stack.length) {
var item = stack.shift();
result.push(item);
var childs = item.children;
if (childs) {
for (var i = 0; i < childs.length; i++) {
stack.push(childs[i]);
}
}
}
}
var result1 = [];
widthTraversal(dom, result1);
for (var x = result1.length - 1; x >= 0; x--) {
var item = result1[x];
var noRemoveTags = ["IMG", "INPUT", "TABLE", "VIDEO"];
if (item.children.length == 0 && item.innerHTML == "" && noRemoveTags.indexOf(item.tagName) == -1) {
item.parentNode.removeChild(item);
}
}
console.log(result1);
console.log($(dom).html());
</script>
其他：
https://segmentfault.com/q/1010000007407908?_ea=1336748
let reg = /<([a-z]+?)(?:\s+?[^>]*?)?>\s*?<\/(?!img)\1>/ig
