数据结构-哈夫曼(Huffman)


#include <iostream>
#include <cstdio>
#include <malloc.h>
#define LIST_INIT_SIZE 10
#define LISTINCREMENT 100
#define TRUE 1
#define FALSE 0
#define OK 1
#define ERROR 0
#define INFEASIBLE -1
#define OVERFLOW -2
#define MAX 0xcfcfcfcf
using namespace std;

typedef struct
{
    unsigned int weight;
    unsigned int parent, lchild, rchild;
} HTNode, *HUffmanTree;
void select(HUffmanTree HT, int n, int *s1, int *s2);
void found(HUffmanTree ht, int i, int j, char *c);
void HUffmanCoding(HUffmanTree *HT, int *w, int n);

int main()
{
    char c[10];
    int w[10] = {5,29,7,8,14,23,3,11};
    HUffmanTree HT;
    HUffmanCoding(&HT,w,8);//8是数组长度
    for(int i=0; i<8; i++) printf("%d%c",w[i],i==7?'\n':' ');
    found(HT,14,0,c);//14是树根所在位置
    return 0;
}


void select(HUffmanTree HT, int n, int *s1, int *s2)
{
    unsigned int min1, min2;
    min1 = min2 = MAX;
    for(int i = 0; i < n; i++)
    {
        if(HT[i].weight <= min1&& !HT[i].parent)
        {
            min2 = min1;
            *s2 = *s1;
            min1 = HT[i].weight;
            *s1 = i;
        }
        else if(HT[i].weight < min2&& !HT[i].parent)
        {
            min2 = HT[i].weight, *s2 = i;
        }
    }
}

void found(HUffmanTree ht, int i, int j, char *c)
{
    if(ht[i].lchild==0 && ht[i].rchild==0)
    {
        c[j] = '\0';
        printf("i:%-2d w:%-2d char:%s\n", i, ht[i].weight, c);
        return;
    }
    c[j] = '1';
    found(ht,ht[i].lchild,j+1,c);
    c[j] = '0';
    found(ht,ht[i].rchild,j+1,c);
    return;
}

void HUffmanCoding(HUffmanTree *HT, int *w, int n)
{
    int s1, s2;
    if(!n) return;
    *HT = (HUffmanTree)malloc((2*n)*sizeof(HTNode));
    HUffmanTree p = *HT;
    for(int i = 0; i< n; i++)
    {
        p[i].lchild = p[i].rchild = p[i].parent = 0;
        p[i].weight = w[i];
    }
    for(int i =n; i < 2*n; i++)
    {
        p[i].weight = p[i].lchild = p[i].rchild = p[i].parent = 0;
    }
    for(int i = n; i < 2*n-1; i++)
    {
        select(*HT, i, &s1, &s2);
        p[s1].parent = i, p[s2].parent = i;
        p[i].lchild = s1, p[i].rchild = s2;
        p[i].weight = p[s1].weight + p[s2].weight;
    }
    printf("Weight parent lchild rchild\n");
    for(int i = 0; i < 2*n-1; i++)
        printf("   %-4d  %-4d   %-4d   %-4d\n",p[i].weight, p[i].parent, p[i].lchild, p[i].rchild);
    printf("----------------------------------\n");
    return;
}



posted @ 2017-01-02 21:48  一根咸鱼干  阅读(388)  评论(0编辑  收藏  举报