1124. Raffle for Weibo Followers (20)
1124. Raffle for Weibo Followers (20)
John got a full mark on PAT. He was so happy that he decided to hold a raffle(抽奖) for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.
Input Specification:
Each input file contains one test case. For each case, the first line gives three positive integers M (<= 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.
Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.
Output Specification:
For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print "Keep going..." instead.
Sample Input 1:9 3 2 Imgonnawin! PickMe PickMeMeMeee LookHere Imgonnawin! TryAgainAgain TryAgainAgain Imgonnawin! TryAgainAgainSample Output 1:
PickMe Imgonnawin! TryAgainAgainSample Input 2:
2 3 5 Imgonnawin! PickMeSample Output 2:
Keep going...
思路:思路很简单上面已经说了。我选择vector<string>存储,用字符数组也没问题。但是,用vector<string>有一个特别坑的地方,它的 num.size(),返回的不是int,而是无符号整数(unsigned int),所以不能直接和int做 > < 比较。
代码:
#include<iostream> #include<string> #include<vector> using namespace std; int main() { int m, n, s, i, j; cin >> m >> n >> s; vector<string> people; vector<string> winner; string tmp; for (int i = 0; i < m; i++) { cin >> tmp; people.push_back(tmp); } s--;//模拟从1开始计数 if (s >= m) { cout << "Keep going..." << endl; return 0; } else { while (s < m) { int size = winner.size();//将unsigned int 转化为 int for (i = 0; i < size; i++) if (winner[i] == people[s]) break; if (i != size) s++; else { cout << people[s] << endl; winner.push_back(people[s]); s += n; } } } return 0; }