如何转换指定 波长 到 RGB 颜色?
//指定波长转换成RGBA颜色
std::vector<int> lambdaToColor(double lambda,double gamma = 0.8,double intensityMax = 255.0)
{
double r, g, b, alpha;
if (lambda >= 380.0 && lambda < 440.0) {
r = -1.0 * (lambda - 440.0) / (440.0 - 380.0);
g = 0.0;
b = 1.0;
}else if (lambda >= 440.0 && lambda < 490.0) {
r = 0.0;
g = (lambda - 440.0) / (490.0 - 440.0);
b = 1.0;
}else if (lambda >= 490.0 && lambda < 510.0) {
r = 0.0;
g = 1.0;
b = -1.0 * (lambda - 510.0) / (510.0 - 490.0);
}else if (lambda >= 510.0 && lambda < 580.0) {
r = (lambda - 510.0) / (580.0 - 510.0);
g = 1.0;
b = 0.0;
}else if (lambda >= 580.0 && lambda < 645.0) {
r = 1.0;
g = -1.0 * (lambda - 645.0) / (645.0 - 580.0);
b = 0.0;
}else if (lambda >= 645.0 && lambda <= 780.0) {
r = 1.0;
g = 0.0;
b = 0.0;
}else {
r = 0.0;
g = 0.0;
b = 0.0;
}
//在可见光谱的边缘处强度较低。
if (lambda >= 380.0 && lambda < 420.0) {
alpha = 0.30 + 0.70 * (lambda - 380.0) / (420.0 - 380.0);
}else if (lambda >= 420.0 && lambda < 701.0) {
alpha = 1.0;
}else if (lambda >= 701.0 && lambda < 780.0) {
alpha = 0.30 + 0.70 * (780.0 - lambda) / (780.0 - 700.0);
}else {
alpha = 0.0;
}
//1953年在引入NTSC电视时,计算具有荧光体的监视器的亮度公式如下
int Y = static_cast<int>(0.212671*r + 0.715160*g + 0.072169*b);
//伽马射线 gamma
//照明强度 intensityMax
int R = r == 0.0 ? 0 : static_cast<int>(std::round(intensityMax * std::pow(r * alpha, gamma)));
int G = g == 0.0 ? 0 : static_cast<int>(std::round(intensityMax * std::pow(g * alpha, gamma)));
int B = b == 0.0 ? 0 : static_cast<int>(std::round(intensityMax * std::pow(b * alpha, gamma)));
int A = static_cast<int>(alpha);
return std::vector<int>{R, G, B, A, Y};
}
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