日期时间练习题一

Java

import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

public static void  dayByDay() throws Exception {
        
        String str1 = "2019-10-10 08:30:00";
        String str2 = "2019-10-11 11:00:00";
        
        SimpleDateFormat spf = new SimpleDateFormat("yyyy-MM-dd HH:mm:SS");
        Date date11 = spf.parse(str1);
        Date date22 = spf.parse(str2);

        Calendar c = Calendar.getInstance();
        
        long time1 = date11.getTime();
        long time2 = date22.getTime();
        
        c.setTimeInMillis(time2-time1);        
        int day1 = c.get(Calendar.DAY_OF_MONTH);
        int hour1 = c.get(Calendar.HOUR);
        int min1 = c.get(Calendar.MINUTE);
        int sec1 = c.get(Calendar.SECOND);
        
        c.setTimeInMillis(0);
        int day2 = c.get(Calendar.DAY_OF_MONTH);
        int hour2 = c.get(Calendar.HOUR);
        int min2 = c.get(Calendar.MINUTE);
        int sec2 = c.get(Calendar.SECOND);
        System.out.println("时间差："+(day1-day2)+"天"+(hour1-hour2)+"小时"+(min1-min2)+"分"+(sec1-sec2)+"秒");
        
    }

 

Python

import time

time1 = time.mktime(time.strptime('2019-10-10 08:30:00', '%Y-%m-%d %H:%M:%S'))  # 时间字符串 -> 结构化时间 -> 时间戳
time2 = time.mktime(time.strptime('2019-10-11 11:00:00', '%Y-%m-%d %H:%M:%S'))  #    strptime()     mktime()
dif_time = time2-time1  # 时间戳做差
struct_time = time.localtime(dif_time)  # 时间戳 -> 结构化时间
print('时间差 %d年%d月%d天%d小时%d分钟%d秒' % (struct_time.tm_year-1970, struct_time.tm_mon-1,
                                       struct_time.tm_mday-1, struct_time.tm_hour,
                                       struct_time.tm_min, struct_time.tm_sec))