实验6

实验结论

Part1: 结构体类型及编程应用

1.补足程序ex1_2.cpp，附上补足后的程序源码，输入不同测试数据，给出运行结果截图

#include <stdio.h>
const int N = 5;
typedef struct student {
    long no;
    char name[20];
    int score;
}STU;
void input(STU s[], int n);
int findMinlist(STU s[], STU t[], int n);
void output(STU s[], int n);
int main() {
    STU stu[N], minlist[N];
    int count;
    printf("please enter %d students' information\n", N);
    input(stu, N);
    printf("\nadding the number of students in the lowest scores and their information...\n");
    count = findMinlist(stu, minlist, N);
    printf("\n there are %d lowest score,here are the information:\n", count);
    output(minlist, count);
    return 0;
}
void input(STU s[], int n) {
    int i;
    for (i = 0; i < n; i++)
        scanf("%ld %s %d", &s[i].no, s[i].name, &s[i].score);
}
void output(STU s[], int n) {
    int i;
    for (i = 0; i < n; i++)
        printf("%ld %s %d\n", s[i].no, s[i].name, s[i].score);
}
int findMinlist(STU s[], STU t[], int n) {
int i,k=0,min=s[0].score;
for(i=0;i<n;i++){
if(s[i].score<min)
min=s[i].score;
}
for(i=0;i<n;i++){
if(s[i].score==min)
t[k++]=s[i];}
return k;
}

2.补足程序ex1_3.cpp，附上补足后的程序源码，输入不同测试数据，给出运行结果截图

#include <stdio.h>
#include <string.h>
const int N = 10;
typedef struct student {
long int id;
char name[20];
float objective; 
float subjective; 
float sum;
char level[10];
}STU;
void input(STU s[], int n);
void output(STU s[], int n);
void process(STU s[], int n);
int main() {
STU stu[N];
printf("enter %d candidates' information: admission ticket,name,objective(<=40),subjective(<=60)\n",
N);
input(stu, N);
printf("\n manage the candidates' information:caclulate total scores,set the level\n");
process(stu, N);
printf("\nprint the candidates' information: admission ticket,name,objective,subjective\n");
output(stu, N);
return 0;
}
void input(STU s[], int n) {
int i;
for(i=0;i<n;i++)
scanf("%ld %s %f %f",&s[i].id,s[i].name,&s[i].objective,&s[i].subjective);
}
void output(STU s[], int n) {
int i;
for(i=0;i<n;i++)
printf("%ld %s %f %f %f %s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level);
}
void process(STU s[], int n) {
    int i,j;
    STU temp;
    for(i=0;i<n;i++)
    s[i].sum=s[i].objective+s[i].subjective;
    for(i=0;i<n;i++){
     for(j=0;j<n-1-i;j++){
         if(s[j].sum<s[j+1].sum){
             temp=s[j];
             s[j]=s[j+1];
             s[j+1]=temp;
         }
     }
     
    }
     strcpy(s[0].level,"A" );        
    for(i=1;i<=4;i++){
        strcpy(s[i].level,"B");
    } 
    for(i=5;i<=9;i++){
        strcpy(s[i].level,"C");

    }
}

 

Part2: 共用体类型及编程示例

总结： 共用体与结构体类型的区别？

共同体：共同占用同段内存

结构体：有独立内存空间

 

 

Part3: 枚举类型及编程示例

总结：

1.枚举类型用于描述哪一类数据？ 

整型常量；

2.枚举变量使用过程中的注意事项

能否直接输入输出？ 能否把一个int型数值赋值给一个枚举类型的变量？反过来呢？

不能；不能，需显式转换；反过来可以

 

实验总结和体会

心力交瘁有点困