摘要: 连接查询:select table_b.type,table_b.title,table_b.content,table_b.author from table_a left join table_b on table_a.type = table_b.type where table_a.id = 阅读全文
posted @ 2017-12-04 10:18 learn_by_doing 阅读(388) 评论(0) 推荐(0) 编辑