Oracle ROW_NUMBER() OVER()函数用法详解 (分组排序 例子多)
转载☞:https://blog.csdn.net/qq_25221835/article/details/82762416
ROW_NUMBER
语法
语法格式:row_number() over(partition by 分组列 order by 排序列 desc)
解释
row_number() over()分组排序功能:
在使用 row_number() over()函数时候,over()里头的分组以及排序的执行晚于 where 、group by、 order by 的执行。
示例1
表数据:
create table TEST_ROW_NUMBER_OVER( id varchar(10) not null, name varchar(10) null, age varchar(10) null, salary int null ); select * from TEST_ROW_NUMBER_OVER t; insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(1,'a',10,8000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(1,'a2',11,6500); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(2,'b',12,13000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(2,'b2',13,4500); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(3,'c',14,3000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(3,'c2',15,20000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(4,'d',16,30000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(5,'d2',17,1800);
依次排序:对查询结果进行排序(无分组)
select id,name,age,salary,row_number()over(order by salary desc) rn from TEST_ROW_NUMBER_OVER t
结果
根据id分组排序
select id,name,age,salary,row_number()over(partition by id order by salary desc) rank from TEST_ROW_NUMBER_OVER t
结果
找出每一组中序号为一的数据
select * from(select id,name,age,salary,row_number()over(partition by id order by salary desc) rank from TEST_ROW_NUMBER_OVER t) where rank <2
结果
排序找出年龄在13岁到16岁数据,按salary排序
select id,name,age,salary,row_number()over(order by salary desc) rank from TEST_ROW_NUMBER_OVER t where age between '13' and '16'
结果:结果中 rank 的序号,其实就表明了 over(order by salary desc) 是在where age between and 后执行的
示例二
使用row_number()函数进行编号
select email,customerID, ROW_NUMBER() over(order by psd) as rows from QT_Customer
在订单中按价格的升序进行排序,并给每条记录进行排序代码如下:
select DID,customerID,totalPrice,ROW_NUMBER() over(order by totalPrice) as rows from OP_Order
统计出每一个各户的所有订单并按每一个客户下的订单的金额 升序排序,同时给每一个客户的订单进行编号。这样就知道每个客户下几单了
select ROW_NUMBER() over(partition by customerID order by totalPrice) as rows,customerID,totalPrice, DID from OP_Order
统计每一个客户最近下的订单是第几次下的订单
with tabs as ( select ROW_NUMBER() over(partition by customerID order by totalPrice) as rows,customerID,totalPrice, DID from OP_Order ) select MAX(rows) as '下单次数',customerID from tabs group by customerID
筛选出客户第一次下的订单
思路。利用rows=1来查询客户第一次下的订单记录
with tabs as ( select ROW_NUMBER() over(partition by customerID order by insDT) as rows,* from OP_Order ) select * from tabs where rows = 1 select * from OP_Order
注意:在使用over等开窗函数时,over里头的分组及排序的执行晚于“where,group by,order by”的执行。
select ROW_NUMBER() over(partition by customerID order by insDT) as rows, customerID,totalPrice, DID from OP_Order where insDT>'2011-07-22'