循环链表(隔M杀1)

<!doctype html>
<html lang="en">
<head>
	<meta charset="UTF-8">
	<title>隔m杀1</title>
</head>
<body>
	
</body>
</html>
<script>
(function(w){
function Person(ele){
	this.ele = ele;
	this.next = null;
}
w.List = function(){
	this.head = new Person(1);
	this.head.next = this.head;
}
List.prototype={
	//插入item元素后面
	insert:function(newPer,item){
		var later = item.next;
		item.next = newPer;
		newPer.next= later;
	},
	//查找元素
	find:function(item){
		var current = this.head;
		while(current.next !== this.head && current.next !== item){
			current = current.next;
		}
		return current;
	},
	//打印所有元素
	print:function(){
		var current =this.head;
		var str = current.ele;
		while(current.next !== this.head){
			current = current.next;
			str += ","+current.ele;
		}
		document.write(str);
	},
	//快速生成链表元素
	add:function(m){
		var temp;
		var count;
		if(m>1){
			count = 2;
			temp =  new Person(2);
			this.head.next =temp;
			while(++count <= m){
				this.insert(new Person(count),temp);
				temp = temp.next;
			}	
			temp.next = this.head;	
		}
	},
	//找到元素
	find:function(item){
		var current = this.head;
		while(current.ele !== item && current.next !== this.head){
			current = current.next;
		}
		return current;
	},
	//找到前一个
	findpre:function(item){
		var current = this.head;
		var pre;
		while(current.ele !== item && current.next !== this.head ){
			pre = current;
			current = current.next;
		}
		return pre;
	},
	//找到后面第几位
	findLater:function(item,n){
		var current = this.find(item);
		var count = 0;
		while(++count <= n){
			current = current.next;
		}
		return current;
	},
	//实时链表长度
	len:function(){
		var count=1;
		var current = this.head;
		while(current.next !== this.head){
			count++;
			current = current.next;
		}
		return count;
	}
}
})(window)
//任务:40人隔3杀1
function game(n,m){
	var list = new List();
	list.add(n);
	var del,pre;
	var current = list.head;
	while(list.len() >= m){
		del = list.findLater(current.ele,m-1);
		if(del === list.head){
			list.head = list.head.next;
		}
		pre = list.findpre(del.ele);
		pre.next = del.next;
		current = list.findLater(current.ele,m-1)
	}
	list.print();
}
game(1000,3)
</script>

  

posted @ 2016-12-18 14:02  chenxiZ  阅读(236)  评论(0编辑  收藏  举报