摘要:
1 program hehe; 2 var 3 n,m,i,j,q,x1,y1,x2,y2,co:longint; 4 y:array[0..300,0..300] of longint; 5 x:array[0..100,0..300,0..300] of longint; 6 7 ... 阅读全文
摘要:
1 program hehe; 2 var 3 ans,n,r,i,j,k,x,y:longint; 4 c:array[-10..5000,-10..5000] of longint; 5 begin 6 readln(n,r); 7 for i:=1 to n do 8 begin ... 阅读全文
摘要:
1 program hehe; 2 var 3 n,m,i,j:longint; 4 c:array[0..50] of longint; 5 6 function min(a,b:longint):longint; 7 begin 8 if a>b then exit(b);... 阅读全文
摘要:
2748: [HAOI2012]音量调节Time Limit:3 SecMemory Limit:128 MBSubmit:827Solved:548[Submit][Status][Discuss]Description一个吉他手准备参加一场演出。他不喜欢在演出时始终使用同一个音量,所以他决定每一... 阅读全文