Newtonsoft.Json 与 DataTable的相互转换

创建一个DataTable对象：

 1         DataTable dt = new DataTable();
 2         DataColumn dcName = new DataColumn("Name");
 3         DataColumn dcAge = new DataColumn("Age");
 4         DataColumn dcCity = new DataColumn("City");
 5 
 6         dt.Columns.Add(dcName);
 7         dt.Columns.Add(dcAge);
 8         dt.Columns.Add(dcCity);
 9         for (int i = 0; i < 10; i++)
10         {
11             DataRow dr = dt.NewRow();
12             dr[0] = "Name" + i;
13             dr[1] = "Age" + i;
14             dr[2] = "City" + i;
15             dt.Rows.Add(dr);
16         }

 转换为json格式：

1         string json = JsonConvert.SerializeObject(dt);
2         Console.WriteLine(json);

json格式转换为DataTable：

1         DataTable dt1 = JsonConvert.DeserializeObject<DataTable>(json);
2         for (int i = 0; i < dt1.Rows.Count; i++)
3         {
4             DataRow dr = dt1.Rows[i];
5             Console.WriteLine("{0}\t{1}\t{2}\t", dr[0], dr[1], dr[2]);
6         }

 

摘自：http://www.cnblogs.com/08shiyan/p/3464028.html

posted @ 2014-06-10 08:02  陈少鑫  阅读(3546)  评论(0)  编辑  收藏  举报