22/7第300位小数 (递归实现)

22/7取第300位小数，代码如下：

public Int32 Result(Int32 d1, Int32 d2,Int32 nowCount,Int32 endCount)
       {
           if(d1<d2){
           d1*=10;
           }
           if (nowCount == endCount)
           {
               return d1 / d2;
           }
           else
           {
               return Result(d1 % d2, d2, ++nowCount,endCount);
           }
       }

测试的代码如下：

 [TestMethod()]
        public void ResultTest()
        {
            //3.14285714285714
            TwentyTwoDivisionSeven target = new TwentyTwoDivisionSeven();
            Assert.AreEqual(1, target.Result(22, 7, 0, 1));

            Assert.AreEqual(4, target.Result(22, 7, 0, 2));

            Assert.AreEqual(2, target.Result(22, 7, 0, 3));

            Assert.AreEqual(8, target.Result(22, 7, 0, 4));

            Assert.AreEqual(8, target.Result(22, 7, 0, 10));

            Assert.AreEqual(7, target.Result(22, 7, 0, 300));
        }