C# 应用 mysql数据在datagrideview上显示
核心代码如下
1、引用动态链路库文件
2、添加dataGridView1控件与botton控件
using MySql.Data.MySqlClient; private void button1_Click(object sender, EventArgs e) { GetMessage(); } private DataTable GetMessage() { string P_Str_ConnectionStr = string.Format("server={0};user id = {1};password = {2};port = {3};database=jeecg;pooling = false;", "10.8.100.156", "xixismile","12345678", 3306); string P_Str_SqlStr = string.Format("select id as 序列ID,create_name as 用户名 from beijian_record"); MySqlDataAdapter adapter = new MySqlDataAdapter(P_Str_SqlStr,P_Str_ConnectionStr); DataTable P_dt = new DataTable(); adapter.Fill(P_dt); this.dataGridView1.DataSource = P_dt; return P_dt; }
posted on 2018-11-08 14:08 肚子咕咕叫是不是饿了 阅读(171) 评论(0) 编辑 收藏 举报