摘要: Given an integer n, return the number of trailing zeroes in n!. Note: Your solution should be in logarithmic time complexity. 这个是我的代码,但是超时 class Solution { public: int trailingZeroes(int ... 阅读全文
posted @ 2014-12-30 21:26 程序员小王 阅读(106) 评论(0) 推荐(0) 编辑