2018年6月7日

好的Mysql 查询语句

摘要: select swr.id,swr.name,swr.sort as type,count(swl.id) as nums,ifnull(sum(swl.package_num),0) packageNum from sys_warehouse_roadway swr left join sys_w 阅读全文

posted @ 2018-06-07 14:13 chengjunde 阅读(103) 评论(0) 推荐(0) 编辑

导航