python--查询员工信息

[root@cheeron lesson1]# cat user.txt
1 cheeron python 4099822
2 forilen shell 12309865
3 XueLi JS 4321780
4 LiLei IT 48393022
5 Simith IT 2340987
6 Liudehua Python 1234567
7 cheeron python 4099822
8 forilen shell 12309865
9 XueLi JS 4321780
10 LiLei IT 48393022
11 Simith IT 2340987
12 Liudehua Python 1234567

#!/usr/bin/env python

staff_list = 'user.txt'

f = open(staff_list)

c = f.readlines()

while True:

　　user_input = raw_input('\033[32;1mPls input sth to search:\033[0m ').strip()

　　if len(user_input) == 0: continue

　　for line in c:

　　　　if user_input in line:

　　　　　　print line

　　　　　　break

　　else:

　　　　print '\033[31;1mnot a vaild input!\033[0m' 

 

解决1次只匹配单行的问题，增加一个key，作为信号量，当匹配时则为key赋值为1，否则为0.

 
  1 #!/usr/bin/env python
  2 staff_list = 'user.txt'
  3 f = open(staff_list)
  4 c = f.readlines()
  5 while True:
  6     user_input = raw_input('\033[32;1mpls input sth to search:\033[0m ').strip()
  7     if len(user_input) == 0:continue
  8     key=0
  9     for line in c:
 10         if user_input in line:
 11             print line
 12             key=1
 13     if key == 0:
 14         print '\033[31;1mnot a vaild key word!\033[0m'

 

 结果：

pls input sth to search: LiLei
4 LiLei         IT                      48393022

10 LiLei                IT                      48393022

pls input sth to search: