Python练习题：有一个6位数，它的2倍、3倍、4倍、5倍、6倍都由原数的6个数字组成，只是顺序不同，求这个6位数

题目：有一个6位数，它的2倍、3倍、4倍、5倍、6倍都由原数的6个数字组成，只是顺序不同，求这个6位数。

#!/usr/bin/python3
# -*- encoding:utf-8 -*-
#检查每一位数字是否存在于倍数结果中
def check(result,num):
    length = len(num)
    count = 0 
    for i in range(length):
        if str(num[i]) in str(result):
            count +=1
        else:
            break
    return count
#循环六位数
for i in range(100000,999999):
#倍数结果
    two = i * 2
    three = i * 3
    four = i * 4
    five = i * 5
    six = i * 6
#抽取每位数字存到列表中
    list = []
    a = i % 10
    b = int( i / 10  %10 )
    c = int( i / 100 %10 )
    d = int( i / 1000 %10 )
    e = int( i / 10000 %10 )  
    f = int( i / 100000 %10 )
    list.append(a)
    list.append(b)
    list.append(c)
    list.append(d)
    list.append(e)
    list.append(f)
#判断是否有数字重复
    if a == b or b == c or c == d or d == e or e == f:
        pass
    elif check(two,list) == 6 and check(three,list) == 6 and check(four,list) == 6 and check(five,list) == 6 and check(six,list) == 6:
        print("{} is ok".format(i))
    else:
        pass

更优解：

#!/usr/bin/python3
# -*- encoding:utf-8 -*-
#检查每一位数字是否存在于倍数结果中
def check(num):
    origlist = set(list(str(x)))
    x2list = set(list(str(x * 2)))
    x3list = set(list(str(x * 3)))
    x4list = set(list(str(x * 4)))
    x5list = set(list(str(x * 5)))
    x6list = set(list(str(x * 6)))
    if origlist == x2list == x3list == x4list == x5list == x6list:
        return True
    return False

'''
    print(origlist)
    print(x2list)
    print(x3list)
    print(x4list)
    print(x5list)
    print(x6list)
'''

for x in range(100000,200000):
    if check(x):
        print(x)