HDU2896 病毒侵袭 AC自动机模板

各种MLE，这模板感觉有问题，next数组开128也会MLE，实际上可见字符为编号32~126，只用开100就行。

  1 #include <iostream>
  2 #include <cstdio>
  3 #include <string.h>
  4 #include <algorithm>
  5 #include <queue>
  6 #pragma warning ( disable : 4996 )
  7 using namespace std;
  8 
  9 inline int Max(int a,int b) { return a>b?a:b; }
 10 inline int Min(int a,int b) { return a>b?b:a; }
 11 const int inf = 0x3f3f3f3f;
 12 const int maxn = 1e6+5;
 13 const int maxk = 100;
 14 
 15 int N, M, tot;
 16 int ans[5];
 17 char str[205], test[10005];
 18 
 19 struct node {
 20     node* next[maxk];
 21     node* fail;
 22     int code;
 23     bool end;
 24     node() {
 25         memset( next, NULL, sizeof(next) );
 26         fail = NULL;
 27         code = 0; end = false;
 28     }
 29 };
 30 
 31 void insert( node* root, int x )
 32 {
 33     node* p = root;
 34     int len = strlen(str);
 35     int tmp;
 36 
 37     for ( int i = 0; i < len; i++ )
 38     {
 39         tmp = str[i]-32;
 40         if ( p->next[tmp] == NULL )
 41             p->next[tmp] = new node();
 42         p = p->next[tmp];
 43         p->code = x;
 44     }
 45     p->end = true;
 46 }
 47 
 48 void getnotfail( node* root )
 49 {
 50     queue<node*> q;
 51     root->fail = NULL;
 52     q.push(root);
 53     while (!q.empty())
 54     {
 55         node *run= q.front(); q.pop();
 56         node *tmp = NULL;
 57         for ( int i = 0; i < maxk; i++ )
 58         {
 59             if ( run->next[i] )
 60             {    //如果节点是初始节点，则它的子节点的失败指针全部指向root
 61                 if(run==root) run->next[i]->fail = root;
 62                 else
 63                 {
 64                     tmp = run->fail;        //tmp为它的父节点的上层节点
 65                     while (tmp)
 66                     {
 67                         if(tmp->next[i])    //寻找tmp的第i个子节点,如果存在，则run的fail指针指向它
 68                         { run->next[i]->fail = tmp->next[i]; break; }
 69                         tmp = tmp->fail;
 70                     }
 71                     if(tmp==NULL)
 72                         run->next[i]->fail = root;
 73                 }
 74                 q.push(run->next[i]);
 75             }
 76         }
 77     }
 78 }
 79 
 80 int query( node* r )
 81 {
 82     int cnt = 0;
 83     int len = strlen(test);
 84     node* p = r;
 85     for ( int i = 0; i < len; i++ )
 86     {
 87         int x = test[i]-32;
 88         while (!p->next[x]&&p!=r) p = p->fail;
 89         
 90         p = p->next[x];
 91         if (!p) p = r;
 92         node *tmp = p;
 93 
 94         while (tmp!=r&&tmp->end)
 95         {
 96             ans[cnt++] = tmp->code;
 97             tmp = tmp->fail;
 98         }
 99     }
100     return cnt;
101 }
102 
103 int main()
104 {
105 
106     while ( ~scanf("%d", &N ))
107     {
108         node* r = new node;
109 
110         for ( int i = 1; i <= N; i++ )
111         { scanf("%s", str); insert(r, i); }
112         getnotfail(r);
113         cin >> M;
114 
115 
116         for ( int i = 1; i <= M; i++ )
117         {
118             scanf( "%s", test );
119             int num = query(r);
120             if (num)
121             {
122                 sort(ans, ans + num);
123                 printf( "web %d:", i );
124                 for ( int j = 0; j < num; j++ )
125                     printf(" %d", ans[j]);
126                 cout << endl;
127                 tot++;
128                 memset( ans, 0, sizeof(ans) );
129             }
130         }
131         printf("total: %d\n", tot);
132     }
133     return 0;
134 }
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posted @ 2018-03-25 11:22  LBNOQYX  阅读(128)  评论(0)  编辑  收藏  举报