一元二次方程的因式分解
摘要:
/*** 求因式分解* @author tiger* @date 2010-08-23*/public class fenjie {public int a ;public int b ;public int c ;public void print(){String str = "";if(a == 1){str += "x^2";}else if(a > 0 || a < 0){str += a + "x^2";}if(b == 1){str += " + " + "x" ;}e 阅读全文
posted @ 2010-08-30 00:37 台哥编程课堂 阅读(384) 评论(0) 推荐(0) 编辑